Submission #243596

#TimeUsernameProblemLanguageResultExecution timeMemory
243596osaaateiasavtnlWorst Reporter 3 (JOI18_worst_reporter3)C++14
12 / 100
2075 ms12664 KiB
#include<bits/stdc++.h>     
using namespace std;
#define int long long
#define ii pair <int, int>
#define app push_back
#define all(a) a.begin(), a.end()
#define bp __builtin_popcountll
#define ll long long
#define mp make_pair
#define f first
#define s second
#define Time (double)clock()/CLOCKS_PER_SEC
#define debug(x) std::cout << #x << ": " << x << '\n';

const int N = 5e5+7;
int mx[N << 2];
void build(int v, int tl, int tr, vector <int> &a) {
    if (tl == tr) {
        mx[v] = a[tl];
        return;
    }   
    int tm = (tl + tr) >> 1;
    build(v * 2 + 1, tl, tm, a);
    build(v * 2 + 2, tm + 1, tr, a);
    mx[v] = max(mx[v * 2 + 1], mx[v * 2 + 2]);
}   
int getl(int v, int tl, int tr, int l, int r, int x) {
    if (tr < l || r < tl || mx[v] <= x)
        return -1;
    if (tl == tr)
        return tl;
    int tm = (tl + tr) >> 1;
    int t = getl(v * 2 + 1, tl, tm, l, r, x);
    if (t != -1)
        return t;
    else
        return getl(v * 2 + 2, tm + 1, tr, l, r, x);
}   

signed main() {
    #ifdef HOME
    freopen("input.txt", "r", stdin);
    #else
    #define endl '\n'
    ios_base::sync_with_stdio(0); cin.tie(0);
    #endif

    int n, q;
    cin >> n >> q;
    vector <int> d(n);
    for (int i = 0; i < n; ++i)
        cin >> d[i];

    build(0, 0, n - 1, d);            

    while (q--) {
        int t, l, r;
        cin >> t >> l >> r;

        int ans = 0;
        ans += l <= t && t <= r;

        int step = 1, cnt = t, ptr = 0;
        while (ptr < n) {
            int i = getl(0, 0, n - 1, ptr, n - 1, step);
            if (i == -1)
                i = n;
            for (int j = ptr; j < i; ++j) {
                int to = -j-1+cnt*step;
                ans += l <= to && to <= r;
            }   
            if (i == n)
                break;

            int x = (d[i]+step-1)/step;
            int step1 = step * x;
            int cnt1 = cnt/x;
            int to = -i-1 + cnt1 * step1;
            ans += l <= to && to <= r;
            tie(step, cnt) = mp(step1, cnt1);            
            ptr = i+1;
        }   
        cout << ans << endl;
    }   

}
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