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답안 #243444

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
243444 2020-07-01T07:44:21 Z VEGAnn Zoltan (COCI16_zoltan) C++14
42 / 140
 1000 ms 16248 KB 
#include <bits/stdc++.h>
#define all(x) x.begin(),x.end()
#define sz(x) ((int)x.size())
#define i2 array<int,2>
#define PB push_back
using namespace std;
const int N = 2010;
const int oo = 2e9;
const int md = int(1e9) + 7;
i2 f[2][N][N], ans;
vector<int> vc;
int n, a[N];

void SUM(int &x, int y){
    x += y;
    if (x >= md)
        x -= md;
}

void upd(i2 &cr, i2 nw){
    if (nw[0] > cr[0])
        cr = nw; else
    if (nw[0] == cr[0]){
        SUM(cr[1], nw[1]);
    }
}

int main(){
    ios_base::sync_with_stdio(0); cin.tie(0);

#ifdef _LOCAL
    freopen("in.txt","r",stdin);
#endif // _LOCAL

    cin >> n;

    assert(n <= 1000);

    for (int i = 0; i < n; i++) {
        cin >> a[i];
        vc.PB(a[i]);
    }

    sort(all(vc));
    vc.resize(unique(all(vc)) - vc.begin());

    for (int i = 0; i < n; i++)
        a[i] = lower_bound(all(vc), a[i]) - vc.begin();

    f[0][a[0]][a[0]] = {1, 1};

    int mn = a[0], mx = a[0];

    int po = 1;

    for (int i = 1; i < n; i++){
        int tp = (i & 1);

        SUM(po, po);

        mn = min(mn, a[i]);
        mx = max(mx, a[i]);

        for (int men = mn;  men <= mx; men++)
        for (int mex = men; mex <= mx; mex++)
            f[tp][men][mex] = {0, 0};

        f[tp][a[i]][a[i]] = {1, po};

        for (int men = mn;  men <= mx; men++)
        for (int mex = men; mex <= mx; mex++){
            if (f[tp ^ 1][men][mex][0] == 0) continue;

//            cerr << f[tp][men][mex][0] << " " << f[tp][men][mex][1] << '\n';
//            cerr << f[tp ^ 1][men][mex][0] << " " << f[tp ^ 1][men][mex][1] << '\n';

            upd(f[tp][men][mex], f[tp ^ 1][men][mex]);
            upd(f[tp][men][mex], f[tp ^ 1][men][mex]);

//            cerr << f[tp][men][mex][0] << " " << f[tp][men][mex][1] << '\n';

            if (a[i] < men) {
                i2 cur = f[tp ^ 1][men][mex];

                cur[0]++;

                upd(f[tp][a[i]][mex], cur);
            }

            if (a[i] > mex) {
                i2 cur = f[tp ^ 1][men][mex];

                cur[0]++;

                upd(f[tp][men][a[i]], cur);
            }
        }
    }

    int tp = ((n - 1) & 1);

    for (int i = mn; i <= mx; i++)
    for (int j = i; j <= mx; j++)
        upd(ans, f[tp][i][j]);

    cout << ans[0] << " " << ans[1];

    return 0;
}

Subtask #1
42.0 / 140.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 512 KB Output is correct
2 Correct 5 ms 512 KB Output is correct
3 Correct 5 ms 512 KB Output is correct
4 Correct 4 ms 384 KB Output is correct
5 Correct 5 ms 512 KB Output is correct
6 Correct 5 ms 384 KB Output is correct
7 Execution timed out 1091 ms 16248 KB Time limit exceeded
8 Execution timed out 1097 ms 16248 KB Time limit exceeded
9 Execution timed out 1094 ms 16224 KB Time limit exceeded
10 Execution timed out 1098 ms 16248 KB Time limit exceeded
11 Runtime error 7 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
12 Runtime error 8 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
13 Runtime error 7 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
14 Runtime error 8 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
15 Runtime error 8 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
16 Runtime error 7 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
17 Runtime error 8 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
18 Runtime error 8 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
19 Runtime error 7 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
20 Runtime error 8 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)