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답안 #243165

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
243165 2020-06-30T13:06:55 Z VEGAnn Svjetlost (COI18_svjetlost) C++14
69 / 100
 1535 ms 52588 KB 
#include <bits/stdc++.h>
#define sz(x) ((int)x.size())
#define all(x) x.begin(),x.end()
#define PB push_back
using namespace std;
typedef long double ld;
const int N = 400100;
const ld E = 1e-8;
const ld pi = 3.1415926535897;
vector<ld> vc;
int n, pr[N], nt[N], x[N], y[N], nm[N], q;
ld st[4 * N], psh[4 * N];

ld sqr(ld xx) { return xx * xx;}

ld dist(ld x1, ld y1, ld x2, ld y2){
    return sqrt(sqr(x1 - x2) + sqr(y1 - y2));
}

void add(int i, int j){
    ld nw_x = x[j] - x[i];
    ld nw_y = y[j] - y[i];

    ld ang = atan2(nw_y, nw_x);

    if (ang < 0) ang += pi + pi;

    vc.PB(ang);

    ang += pi;

    if (ang >= pi + pi)
        ang -= pi + pi;

    vc.PB(ang);
}

void push(int v){
    if (psh[v] != 0){
        st[v] += psh[v];

        if (v + v + 1 < 4 * N){
            psh[v + v] += psh[v];
            psh[v + v + 1] += psh[v];
        }

        psh[v] = 0;
    }
}

void update(int v, int tl, int tr, int l, int r, ld val){
    push(v);

    if (l > r) return;

    if (tl == l && tr == r) {
        psh[v] += val;
        push(v);
        return;
    }

    int md = (tl + tr) >> 1;

    update(v + v, tl, md, l, min(r, md), val);
    update(v + v + 1, md + 1, tr, max(md + 1, l), r, val);

    st[v] = max(st[v + v], st[v + v + 1]);
}

void add_seg(int i, int j, ld val){
    ld nw_x = x[j] - x[i];
    ld nw_y = y[j] - y[i];

    ld ang = atan2(nw_y, nw_x);

    if (ang < 0) ang += pi + pi;

    int lf = lower_bound(all(vc), ang - E) - vc.begin();

    ang += pi;

    if (ang >= pi + pi)
        ang -= pi + pi;

    int rt = lower_bound(all(vc), ang - E) - vc.begin() - 1;

    if (vc[rt] + E > ang) {
        rt--;
        if (rt < 0)
            rt = sz(vc) - 1;
    }

    if (rt < 0) rt = sz(vc) - 1;

//    cerr << lf << " " << rt << '\n';

    if (lf <= rt){
        update(1, 0, sz(vc) - 1, lf, rt, val);
    } else {
        update(1, 0, sz(vc) - 1, lf, sz(vc) - 1, val);
        update(1, 0, sz(vc) - 1, 0, rt, val);
    }
}

int main(){
    ios_base::sync_with_stdio(0); cin.tie(0);

#ifdef _LOCAL
    freopen("in.txt","r",stdin);
#endif // _LOCAL

    cin >> n;

    for (int i = 0; i < n; i++) {
        cin >> x[i] >> y[i];
        pr[i] = (i - 1 + n) % n;
        nt[i] = (i + 1) % n;
    }

    for (int i = 0; i < n; i++)
        add(i, nt[i]);

    cin >> q;

    for (int i = 0; i < q; i++){
        cin >> nm[i]; nm[i]--;

        int id = nm[i];

        pr[nt[id]] = pr[id];
        nt[pr[id]] = nt[id];

        add(pr[id], nt[id]);
    }

//    vc.PB(0);
//    vc.PB(pi + pi);

    sort(all(vc));

//    int cnt = 1;
//
//    for (int i = 1; i < sz(vc); i++)
//        if (abs(vc[i] - vc[i - 1]) > E)
//            vc[cnt++] = vc[i];
//
//    vc.resize(cnt);

    for (int i = 0; i < n; i++){
        pr[i] = (i - 1 + n) % n;
        nt[i] = (i + 1) % n;
        add_seg(i, nt[i], dist(x[i], y[i], x[nt[i]], y[nt[i]]));
    }
    cout << fixed << setprecision(10) << st[1] << '\n';

    for (int i = 0; i < q; i++){
        int id = nm[i];

        add_seg(pr[id], id, -dist(x[pr[id]], y[pr[id]], x[id], y[id]));
        add_seg(id, nt[id], -dist(x[id], y[id], x[nt[id]], y[nt[id]]));

        pr[nt[id]] = pr[id];
        nt[pr[id]] = nt[id];

        add_seg(pr[id], nt[id], dist(x[pr[id]], y[pr[id]], x[nt[id]], y[nt[id]]));

        cout << fixed << setprecision(10) << st[1] << '\n';
    }

    return 0;
}

Subtask #1
12.0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 384 KB 11 numbers
2 Correct 5 ms 384 KB 41 numbers
3 Correct 5 ms 384 KB 11 numbers
4 Correct 5 ms 512 KB 93 numbers

Subtask #2
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 384 KB 11 numbers
2 Correct 5 ms 384 KB 41 numbers
3 Correct 5 ms 384 KB 11 numbers
4 Correct 5 ms 512 KB 93 numbers
5 Correct 7 ms 896 KB 101 numbers
6 Correct 15 ms 1408 KB 1201 numbers
7 Correct 19 ms 1408 KB 1556 numbers
8 Correct 23 ms 1536 KB 1996 numbers
9 Correct 21 ms 1536 KB 1960 numbers
10 Correct 22 ms 1536 KB 1991 numbers
11 Correct 22 ms 1536 KB 1963 numbers

Subtask #3
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 384 KB found '32934.3604541195', expected '32934.3604541195', error '0.0000000000'
2 Correct 8 ms 896 KB found '31571636.3365447670', expected '31571636.3365447633', error '0.0000000000'
3 Correct 33 ms 4092 KB found '31442617.6286691166', expected '31442617.6286691241', error '0.0000000000'
4 Correct 58 ms 7664 KB found '31424400.0534066260', expected '31424400.0534067489', error '0.0000000000'
5 Correct 244 ms 29148 KB found '3142086769.6889743805', expected '3142086769.6889681816', error '0.0000000000'
6 Correct 224 ms 29156 KB found '3142076120.8714599609', expected '3142076120.8714694977', error '0.0000000000'

Subtask #4
29.0 / 29.0

# 결과 실행 시간 메모리 Grader output
1 Correct 15 ms 1408 KB 1001 numbers
2 Correct 174 ms 14824 KB 15001 numbers
3 Correct 512 ms 30132 KB 44445 numbers
4 Correct 393 ms 30436 KB 22223 numbers
5 Correct 910 ms 51544 KB 88889 numbers

Subtask #5
0 / 31.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 384 KB 11 numbers
2 Correct 5 ms 384 KB 41 numbers
3 Correct 5 ms 384 KB 11 numbers
4 Correct 5 ms 512 KB 93 numbers
5 Correct 7 ms 896 KB 101 numbers
6 Correct 15 ms 1408 KB 1201 numbers
7 Correct 19 ms 1408 KB 1556 numbers
8 Correct 23 ms 1536 KB 1996 numbers
9 Correct 21 ms 1536 KB 1960 numbers
10 Correct 22 ms 1536 KB 1991 numbers
11 Correct 22 ms 1536 KB 1963 numbers
12 Correct 5 ms 384 KB found '32934.3604541195', expected '32934.3604541195', error '0.0000000000'
13 Correct 8 ms 896 KB found '31571636.3365447670', expected '31571636.3365447633', error '0.0000000000'
14 Correct 33 ms 4092 KB found '31442617.6286691166', expected '31442617.6286691241', error '0.0000000000'
15 Correct 58 ms 7664 KB found '31424400.0534066260', expected '31424400.0534067489', error '0.0000000000'
16 Correct 244 ms 29148 KB found '3142086769.6889743805', expected '3142086769.6889681816', error '0.0000000000'
17 Correct 224 ms 29156 KB found '3142076120.8714599609', expected '3142076120.8714694977', error '0.0000000000'
18 Correct 15 ms 1408 KB 1001 numbers
19 Correct 174 ms 14824 KB 15001 numbers
20 Correct 512 ms 30132 KB 44445 numbers
21 Correct 393 ms 30436 KB 22223 numbers
22 Correct 910 ms 51544 KB 88889 numbers
23 Correct 1535 ms 52588 KB 98175 numbers
24 Correct 332 ms 15468 KB 25905 numbers
25 Incorrect 1169 ms 52432 KB 12020th numbers differ - expected: '3269022120.9973678589', found: '3268980900.5691776276', error = '0.0000126094'
26 Halted 0 ms 0 KB -