제출 #242452

#제출 시각아이디문제언어결과실행 시간메모리
242452SorahISAOlympic Bus (JOI20_ho_t4)C++17
0 / 100
50 ms4712 KiB
// #pragma GCC target("avx2") #pragma GCC optimize("O3", "unroll-loops") // #include <bits/extc++.h> // using namespace __gnu_pbds; #include <bits/stdc++.h> using namespace std; #define int long long #define double long double // template <typename T> // using pbds_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; using pii = pair<int, int>; template<typename T> using prior = priority_queue<T, vector<T>, greater<T>>; template<typename T> using Prior = priority_queue<T>; #define X first #define Y second #define ALL(x) (x).begin(), (x).end() #define eb emplace_back #define pb push_back #define fastIO() ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) #define RANDOM() random_device __rd; \ mt19937 __gen = mt19937(__rd()); \ uniform_int_distribution<int> __dis(1, 1E8); \ auto rnd = bind(__dis, __gen) const int INF = 1E18; const int mod = 1E9 + 7; const int maxn = 200 + 5; struct Edge { int u, v, c, d; Edge(int _u = 0, int _v = 0, int _c = 0, int _d = 0) : u(_u), v(_v), c(_c), d(_d) {} }; vector<Edge> edge; int floyd[maxn][maxn]; void init() { for (int i = 0; i < maxn; ++i) { for (int j = 0; j < maxn; ++j) floyd[i][j] = INF; floyd[i][i] = 0; } } int32_t main() { fastIO(); init(); int n, m; cin >> n >> m; for (int i = 0; i < m; ++i) { int u, v, c, d; cin >> u >> v >> c >> d; edge.eb(u, v, c, d); floyd[u][v] = min(floyd[u][v], c); } for (int mid = 1; mid <= n; ++mid) { for (int i = 1; i <= n; ++i) { for (int j = 1; j <= n; ++j) { floyd[i][j] = min(floyd[i][j], floyd[i][mid] + floyd[mid][j]); } } } /* if (floyd[1][n] != INF and floyd[n][1] == INF) { int minC = INF; for (auto e : edge) { // if (floyd[e.u][1] != INF and floyd[n][e.v] != INF) // minC = min(minC, floyd[e.u][1] + floyd[n][e.v] + e.c + e.d); } cout << (minC == INF ? -1 : minC + floyd[1][n]) << "\n"; return 0; } */ int minC = floyd[1][n] + floyd[n][1]; for (auto e : edge) { int min1N = min(floyd[1][n], floyd[e.u][n] + floyd[1][e.v] + e.c); int minN1 = min(floyd[n][1], floyd[e.u][1] + floyd[n][e.v] + e.c); cout << min1N << " " << minN1 << " " << e.d << " " << min1N + minN1 + e.d << "\n"; minC = min(minC, min1N + minN1 + e.d); } cout << (minC >= INF ? -1 : minC) << "\n"; return 0; }
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