제출 #241430

#제출 시각아이디문제언어결과실행 시간메모리
241430abacaba휴가 (IOI14_holiday)C++14
7 / 100
5079 ms3068 KiB
#include <iostream> #include <string> #include <unordered_map> #include <unordered_set> #include <cstring> #include <chrono> #include <vector> #include <map> #include <random> #include <set> #include <algorithm> #include <math.h> #include <cstdio> #include <stdio.h> #include <queue> #include <bitset> #include <cstdlib> #include <deque> #include <cassert> #include <stack> using namespace std; #define mp make_pair #define f first #define se second #define pb push_back #define ppb pop_back #define emb emplace_back #define ll long long #define ull unsigned long long #define cntbit(x) __builtin_popcount(x) #define endl '\n' #define uset unordered_set #define umap unordered_map #define pii pair<int, int> #define ld long double #define pll pair<long long, long long> mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); template <typename T> inline T range(T l, T r) { return uniform_int_distribution<T>(l, r)(rng); } inline void setin(string s) { freopen(s.c_str(), "r", stdin); } inline void setout(string s) { freopen(s.c_str(), "w", stdout); } template <typename T> void Min(T &a, T b) { a = min(a, b); } template <typename T> void Max(T &a, T b) { a = max(a, b); } const int inf = 0x3f3f3f3f; const int mod = 998244353; const int N = 1e5 + 15; int a[N]; multiset <int> now; inline ll get(int num) { if(num <= 0) return 0; ll sum = 0; multiset <int>::reverse_iterator it = now.rbegin(); for(int cnt = 0; it != now.rend() && cnt < num; ++it, ++cnt) sum += *it; return sum; } long long findMaxAttraction(int n, int start, int d, int attraction[]) { for(int i = 0; i < n; ++i) a[i] = attraction[i]; ll ans = 0; for(int i = start; i < n; ++i) { now.insert(a[i]); Max(ans, get(d - (i - start))); for(int j = start - 1; j >= 0; --j) { now.insert(a[j]); Max(ans, get(d - (i - j) - (i - start))); } for(int j = start - 1; j >= 0; --j) now.erase(now.find(a[j])); } now.clear(); reverse(a, a + n); start = n - start - 1; for(int i = start; i < n; ++i) { now.insert(a[i]); Max(ans, get(d - (i - start))); for(int j = start - 1; j >= 0; --j) { now.insert(a[j]); Max(ans, get(d - (i - j) - (i - start))); } for(int j = start - 1; j >= 0; --j) now.erase(now.find(a[j])); } return ans; }
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