제출 #240508

#제출 시각아이디문제언어결과실행 시간메모리
240508conankun수열 (APIO14_sequence)Java
60 / 100
499 ms31668 KiB
import java.io.*; import java.util.*; public class sequence { static int N,K; static long S[]; static long D[][]; static short OPT1[][]; static byte OPT2[][]; public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); StringTokenizer st; st = new StringTokenizer(br.readLine()); N = Integer.parseInt(st.nextToken()); K = Integer.parseInt(st.nextToken()); S = new long[N + 1]; D = new long[2][N + 1]; OPT1 = new short[K + 1][N + 1]; OPT2 = new byte[K + 1][N + 1]; st = new StringTokenizer(br.readLine()); for(int i = 1 ; i <= N ; i++) { S[i] = Integer.parseInt(st.nextToken()); S[i] += S[i-1]; } br.close(); solve(); } private static boolean canSkip(int k, int i, int j,int threshold) { return (D[(k-1)%2][i] - D[(k-1)%2][j] + S[N] * (S[j] - S[i])) <= threshold * (S[j] - S[i]); } private static boolean canRemoveLastCandidate(int k, int i, int j, int l) { return (D[(k-1)%2][i] - D[(k-1)%2][j] + S[N] * (S[j] - S[i])) * (S[l] - S[j]) <= (D[(k-1)%2][j] - D[(k-1)%2][l] + S[N] * (S[l] - S[j])) * (S[j] - S[i]); } private static void dp(int k) { int [] candid = new int[N]; int front = 0, back = 0; candid[back++] = k -1; for(int i = k ; i <= N ; i++) { while (back - front > 1 && canSkip(k, candid[front], candid[front + 1], (int) S[i])) { front++; } int j = candid[front]; OPT2[k][i] = (byte)(j / 60000); OPT1[k][i] = (short)(j - OPT2[k][i] * 60000); D[(k%2)][i] = D[(k-1)%2][j] + S[i] * S[j] - S[N] * S[j] + S[N] * S[i] - (S[i] * S[i]); while (back - front > 1 && canRemoveLastCandidate(k, i, candid[back-1], candid[back-2])) { back--; } candid[back++]=i; } } private static void solve() throws IOException { for(int k = 1 ; k <= K ; k++) { Arrays.fill(D[k%2], 0); dp(k); } long ret = 0; int ind = 1; for(int i = 1 ; i <= N ; i++) { if(ret < D[K%2][i]) { ret = D[K%2][i]; ind = i; } } BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out)); bw.write(ret+"\n"); int[] opt = new int[K]; int front = 0; int k = K; while (k > 0) { opt[front++]=ind; ind = (int)OPT2[k][ind] * 60000 + (int)OPT1[k--][ind]; } for(int i = K - 1; i >= 0; i--) { bw.write(opt[i]+" "); } bw.flush(); bw.close(); } }
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