제출 #240503

#제출 시각아이디문제언어결과실행 시간메모리
240503flcat수열 (APIO14_sequence)Java
50 / 100
2081 ms131072 KiB
import java.io.*; import java.util.*; public class sequence { static int N,K; static long S[] = new long[100001]; static long D[][] = new long[2][100001]; static int OPT[][] = new int[201][100001]; static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); static BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out)); public static void main(String[] args) throws IOException { StringTokenizer st; st = new StringTokenizer(br.readLine()); N = Integer.parseInt(st.nextToken()); K = Integer.parseInt(st.nextToken()); st = new StringTokenizer(br.readLine()); for(int i = 1 ; i <= N ; i++) { S[i] = Short.parseShort(st.nextToken()); S[i] += S[i-1]; } solve(); br.close(); bw.flush(); bw.close(); } private static boolean canSkip(int k, int i, int j,int threshold) { return (D[(k-1)%2][i] - D[(k-1)%2][j] + S[N] * (S[j] - S[i])) <= threshold * (S[j] - S[i]); } private static boolean canRemoveLastCandidate(int k, int i, int j, int l) { return (D[(k-1)%2][i] - D[(k-1)%2][j] + S[N] * (S[j] - S[i])) * (S[l] - S[j]) <= (D[(k-1)%2][j] - D[(k-1)%2][l] + S[N] * (S[l] - S[j])) * (S[j] - S[i]); } private static void dp(int k) { List<Integer> candid = new ArrayList<>(); candid.add(candid.size(),k-1); for(int i = k ; i <= N ; i++) { while (candid.size() > 1 && canSkip(k, candid.get(0), candid.get(1), (int) S[i])) { candid.remove(0); } int j = candid.get(0); OPT[k][i] = j; D[k%2][i] = D[(k-1)%2][j] + S[i] * S[j] - S[N] * S[j] + S[N] * S[i] - (S[i] * S[i]); while (candid.size() > 1 && canRemoveLastCandidate(k, i, candid.get(candid.size()-1), candid.get(candid.size()-2))) { candid.remove(candid.size()-1); } candid.add(candid.size(),i); } } private static Vector<Integer> backtrace(int ind) { Vector<Integer> ret = new Vector<>(); new Vector(); int k = K; while (k > 0) { ret.add(ret.size(),ind); ind = OPT[k--][ind]; } Collections.reverse(ret); return ret; } private static void solve() throws IOException { for(int k = 1 ; k <= K ; k++) { Arrays.fill(D[k%2], 0); dp(k); } long ret = 0; int ind = 1; for(int i = 1 ; i <= N ; i++) { if(ret < D[K%2][i]) { ret = D[K%2][i]; ind = i; } } bw.write(ret+"\n"); Vector<Integer> opt = backtrace(ind); for(int x : opt) { bw.write(x+" "); } } }
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