제출 #239181

#제출 시각아이디문제언어결과실행 시간메모리
239181osaaateiasavtnlLinear Garden (IOI08_linear_garden)C++14
36 / 100
392 ms13212 KiB
#include<bits/stdc++.h>
using namespace std;
#define ii pair <int, int>
#define app push_back
#define all(a) a.begin(), a.end()
#define bp __builtin_popcountll
#define ll long long
#define mp make_pair
#define f first
#define s second
#define Time (double)clock()/CLOCKS_PER_SEC

const int C = 3;
int MOD;

int dp1[C][C][2 * C], dp2[C][C][2 * C];

signed main() {
    #ifdef HOME
    freopen("input.txt", "r", stdin);
    #else
    #define endl '\n'
    ios_base::sync_with_stdio(0); cin.tie(0);
    #endif

    int n, MOD;
    string s;
    cin >> n >> MOD >> s;

    for (int mn = 0; mn < C; ++mn)  
        for (int mx = 0; mx < C; ++mx)
            for (int cur = 0; cur < 2 * C; ++cur)
                if (mn + mx <= 2)
                    dp1[mn][mx][cur] = 1;

    vector <int> mn(n + 1), mx(n + 1), cur(n + 1);

    int ans = 1;
    for (int i = 0; i < n; ++i) {
        cur[i + 1] = cur[i];
        if (s[i] == 'P') {
            ++cur[i + 1];
        }   
        else {
            --cur[i + 1];
        }   
        mn[i + 1] = min(mn[i], cur[i + 1]);
        mx[i + 1] = max(mx[i], cur[i + 1]);
    }   

    auto add = [&](int &a, int b) {
        a += b;
        a %= MOD;
    };

    vector <int> can = {-1, 1};
    for (int i = n - 1; i >= 0; --i) {
        if (s[i] == 'P') {
            int cur1 = cur[i]-1;
            int mn1 = max(-mn[i], -cur1);
            int mx1 = max(mx[i], cur1);
            if (mn1 + mx1 <= 2) {
                ans = (ans + dp1[mn1][mx1][cur1+2]);
            }
        }   

        memset(dp2, 0, sizeof dp2);

        for (int mn = 0; mn <= 2; ++mn) {
            for (int mx = 0; mx <= 2; ++mx) {
                for (int cur = -mn; cur <= mx; ++cur) {
                    //shift cur by 2

                    for (int x : can) {
                        int cur1 = cur + x;
                        int mn1 = max(mn, -cur1);
                        int mx1 = max(mx, cur1);
                        if (mn1 + mx1 <= 2) {
                            add(dp2[mn][mx][cur+2], dp1[mn1][mx1][cur1+2]);
                        }   
                    }   

                }   
            }   
        }   

        for (int x = 0; x < C; ++x)
            for (int y = 0; y < C; ++y) 
                for (int z = 0; z < 2 * C; ++z)
                    dp1[x][y][z] = dp2[x][y][z];
    }   

    cout << ans << endl;
}
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