이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("Ofast,unroll-loops")
#pragma GCC target("avx,avx2,fma")
#include <bits/stdc++.h>
using namespace std;
const int N = 101;
int a[N],dp[N][N][N*N/4], L[N][N*N/4] ,n,l,r,k,sum=0;
signed main(){
cin >> n >> l >> r >> k;
for(int i=1;i<=n;++i) cin >> a[i];
sum = accumulate(a+l,a+r+1,sum);
for(int i=l-1;i>0;--i){
for(int j=l;j<=r;++j){
for(int k=0;k<N*N/4;++k){
dp[i][j][k] = max({dp[i][j][k],dp[i+1][j][k],dp[i][j-1][k]});
int spend = j-i;
if(k>=spend) dp[i][j][k] = max(dp[i][j][k],dp[i+1][j-1][k-spend]+a[j]-a[i]);
}
}
}
for(int i=l;i<=r;++i){
for(int j=0;j<N*N/4;++j){
L[i][j] = dp[1][i][j];
}
}
memset(dp,0,sizeof(dp));
for(int i=r;i>=l;--i){
for(int j=r+1;j<=n;++j){
for(int k=0;k<N*N/4;++k){
dp[i][j][k] = max({dp[i][j][k],dp[i-1][j][k],dp[i][j+1][k]});
int spend = j-i;
if(k>=spend) dp[i][j][k] = max(dp[i][j][k], dp[i-1][j+1][k-spend]+a[i]-a[j]);
}
}
}
int ans = 1e9;
for(int i=l;i<=r+1;++i){
for(int j=0;j<N*N/4;++j){
ans = min(ans,sum-L[i-1][j]-dp[i][n][k-j]);
}
}
cout << ans;
}
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