# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
238691 | Vimmer | Spirale (COCI18_spirale) | C++14 | 60 ms | 512 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")
#define F first
#define S second
#define sz(x) int(x.size())
#define pb push_back
#define N 300001
#define M ll(1e9 + 7)
#define inf 1e9 + 1e9
using namespace std;
//using namespace __gnu_pbds;
typedef long double ld;
typedef long long ll;
typedef short int si;
typedef array <int, 2> a2;
//typedef tree <int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
int a[105][105], kr, n, m;
void upd(int x, int y, int val){if (0 <= x && x < n && 0 <= y && y < m) {kr++; a[x][y] = min(a[x][y], val);}}
int main()
{
//freopen("input.txt", "r", stdin); //freopen("output4.txt", "w", stdout);
ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);
int k;
cin >> n >> m >> k;
for (int i = 0; i < n; i++)
for (int j = 0; j < m; j++) a[i][j] = 1e9;
for (int i = 0; i < k; i++)
{
int x, y, t, len = 1, dir = 1, val = 1;
kr = 0;
cin >> x >> y >> t;
x--; y--;
upd(x, y, val);
while (kr < n * m)
{
int kol = 0;
if (t == 1)
{
while (kol < len)
{
kol++; val++;
if (dir == 2) x++;
else if (dir == 1) x--;
else if (dir == 3) y++;
else y--;
upd(x, y, val);
}
if (dir == 1) dir = 4;
else if (dir == 4) {len++; dir = 2;}
else if (dir == 2) dir = 3;
else if (dir == 3) {len++; dir = 1;}
}
else
{
while (kol < len)
{
kol++; val++;
if (dir == 2) x++;
else if (dir == 1) x--;
else if (dir == 3) y++;
else y--;
upd(x, y, val);
}
if (dir == 1) dir = 3;
else if (dir == 3) {len++; dir = 2;}
else if (dir == 2) dir = 4;
else if (dir == 4) {len++; dir = 1;}
}
}
}
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++) cout << a[i][j] << " ";
cout << endl;
}
}
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