이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define loop(i,n) for (ll i = 0; i < n; i++)
#define ll long long
#define INF 1e9+5
#define MAXN 300007
#define pb push_back 
#define mp make_pair
typedef pair<ll,ll> pii;
int main(){
	ll l,r,i,j,k,x,maxi=0;
	cin>>l>>r;
	vector<vector<ll>>row(r);
	vector<vector<ll>>dp(r); 
	for(i=0;i<r;i++){
	cin>>x;
	maxi=max(maxi,x);
	dp[i].pb(0);
	for(j=1;j<=x;j++){
	cin>>k;
	row[i].pb(k);
	dp[i].pb(dp[i][j-1]+k);
	}
}
	if(maxi==1){//só há um por linha
	ll savedL=INF, savedR=-1;
	for(i=0;i<r;i++){
	k=row[i][0];
	savedR = max(savedR , k);
	savedL = min(savedL, l-k-1);
}
	k = savedL+1;
	savedR=max(savedR,savedL+1);
	k+=(l-savedR);
	printf("%lld\n",l-k);
	}else{
	ll left, right,m,cur=0;
	vector<pii>overall;
	for(i=0;i<r;i++){
	m=dp[i][dp[i].size()-1];
	vector<pii>intervals;
	if(m==l){
	cout<<l<<'\n';
	return 0;
}
	for(j=0;j<(ll)dp[i].size();j++){
		left=dp[i][j]+1;
		right=l-(m-left)-1;
		if(left>right)continue;
		intervals.pb({ left,1 });
		intervals.pb({ right+1,-1 });//a partir de right, não está safe
	}
	sort(intervals.begin(),intervals.end());
	for(j=0;j<(ll)intervals.size();j++){
		cur+=intervals[j].second;
		while(j+1<(ll)intervals.size() && intervals[j+1].first==intervals[j].first){
		j++;
		cur+=intervals[j].second;
		}
		if(cur==0){
	//a partir desta posição, os lasers foram apanhados em todas as configurações
		if(j==(ll)intervals.size()-1){
		overall.pb({ intervals[j].first, 1 });
		overall.pb({ l+1, -1 });
		}else{
		overall.pb({ intervals[j].first, 1 });
		overall.pb({ intervals[j+1].first, -1 });
		}
		}
	}
}
	sort(overall.begin(),overall.end());
/*
	for(j=0;j<(ll)overall.size();j++){
		cout<<overall[j].first<<" "<<overall[j].second<<"   ";}
cout<<endl;*/
	cur=0; ll ans=0;
	for(i=0;i<(ll)overall.size();i++){
		if(overall[i].first==l+1)break;
		cur+=overall[i].second;
		while(i<(ll)overall.size()-1 && overall[i+1].first==overall[i].first){
		i++;
		cur+=overall[i].second;
		}
		if(cur>0){
		ans+=(overall[i+1].first-overall[i].first);
		
	}
}
	cout<<ans<<endl;
}
return 0;
}
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