Submission #238264

#	Time	Username	Problem	Language	Result	Execution time	Memory
238264		egekabas	Remittance (JOI19_remittance)	C++14	0 / 100	5 ms	384 KiB

remittance

#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define mp make_pair
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<ll, ll> pll;
typedef pair<ull, ull> pull;
typedef pair<ll, ll> pii;
typedef pair<ld, ld> pld;
ll n;
ll a[1000009], b[1000009];
ll in[1000009], out[1000009];
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    
    //freopen("in.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);
    
    cin >> n;
    for(ll i = 0; i < n; ++i)
        cin >> a[i] >> b[i];
    for(ll i = 0; i < n; ++i){
        ll dif = a[i]-b[i];
        if(dif > 0){
            out[i] = (dif+1)/2;
            in[i] = dif%2;
        }
        else
            in[i] = -dif;
    }
    ll times = 50;
    while(times--){
        for(ll i = 0; i < n; ++i){
            while(in[i] > out[(i-1+n)%n] && out[i] > in[(i+1)%n]){
                in[i] -= 2;
                out[i] -= 1;
            }
            ll bef = (i-1+n)%n;
            if(out[bef] < in[i]){
                in[bef] += (in[i]-out[bef])*2;
                out[bef] = in[i];
            }
            else if(out[bef] > in[i]){
                if((out[bef]-in[i])%2){
                    ++out[bef];
                    in[bef] += 2;
                }
                out[i] += (out[bef]-in[i])/2;
                in[i] = out[bef];
            }
        }
        for(ll i = n-1; i >= 0; --i){
            while(in[i] > out[(i-1+n)%n] && out[i] > in[(i+1)%n]){
                in[i] -= 2;
                out[i] -= 1;
            }
            ll bef = (i-1+n)%n;
            if(out[bef] < in[i]){
                in[bef] += (in[i]-out[bef])*2;
                out[bef] = in[i];
            }
            else if(out[bef] > in[i]){
                if((out[bef]-in[i])%2){
                    ++out[bef];
                    in[bef] += 2;
                }
                out[i] += (out[bef]-in[i])/2;
                in[i] = out[bef];
            }
        }
    }
    
    for(ll i = 0; i < n; ++i){
        ll bef = (i-1+n)%n;
        if(in[i] != out[bef]){
            cout << "No\n";
            return 0;
        }
    }
    cout << "Yes\n";
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 40
• Subtask 3: 0 / 45