| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 238016 | Vimmer | Retro (COCI17_retro) | C++14 | 184 ms | 214048 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("-O3")
#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")
#define F first
#define S second
#define sz(x) int(x.size())
#define pb push_back
#define N 100001
#define M ll(1e9 + 7)
#define inf 1e9 + 1e9
using namespace std;
//using namespace __gnu_pbds;
typedef long double ld;
typedef long long ll;
typedef short int si;
typedef array <int, 2> a2;
//typedef tree <int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
ll f[301][301][301], n, m;
string s[301];
int main()
{
    //freopen("input.txt", "r", stdin); //freopen("output4.txt", "w", stdout);
    ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    cin >> n >> m;
    for (int i = 0; i < n; i++) cin >> s[i];
    int sx, sy;
    for (int i = 0; i < m; i++)
        if (s[n - 1][i] == 'M') {sx = n - 1; sy = i; break;}
    memset(f, -1, sizeof(f));
    f[sx][sy][0] = 0;
    ll I = -1, J, K = -1;
    for (int i = n - 1; i > 0; i--)
        for (int j = 0; j < m; j++)
          for (int st = 0; st <= n - i - 1; st++)
            {
                if (f[i][j][st] == -1 || s[i][j] == '*') continue;
                for (int a = -1; a <= 1; a++)
                    if (a + j >= 0 && a + j < m && (st != 0 || s[i - 1][j + a] != ')'))
                    {
                        ll nw = f[i][j][st], nk = st;
                        if (s[i - 1][j + a] == '(') {nw++; nk++;}
                        if (s[i - 1][j + a] == ')') {nw++; nk--;}
                        if (f[i - 1][j + a][nk] == -1 || f[i - 1][j + a][nk] < nw) f[i - 1][j + a][nk] = nw;
                    }
            }
    for (int i = 0; i < 301; i++)
        for (int j = 0; j < 301; j++)
            if (K < f[i][j][0]) {I = i; J = j; K = f[i][j][0];}
    if (I == -1) cout << 0 << endl;
     else
     {
        cout << K << endl;
        for (int i = 0; i < K; i++) cout << ')';
     }
}
Compilation message (stderr)
| # | Verdict | Execution time | Memory | Grader output | 
|---|---|---|---|---|
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