제출 #237187

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
237187		kartel	Automobil (COCI17_automobil)	C++14	100 / 100	38 ms	16000 KiB

automobil

#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
#define in(x) freopen(x, "r", stdin)
#define out(x) freopen(x, "w", stdout)
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("-O3")
#define F first
#define S second
#define pb push_back
#define N +1000500
#define MaxS N * N
#define M ll(1e9 + 7)
#define sz(x) (int)x.size()
#define re return
#define oo ll(1e18)
#define el '\n'
#define pii pair <int, int>
using namespace std;
//using namespace __gnu_pbds;
//typedef tree <int, null_type, less_equal <int> , rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef long long ll;
typedef long double ld;

ll r[N], c[N], ans, n, m, q, x, y, i, j;
char cmd;

ll mult(ll x, ll y) {return (x * y) % M;}
ll sum(ll x, ll y) {return (x + y) % M;}
ll mi(ll x, ll y) {return (x - y + M) % M;}

ll bp(ll x, ll y)
{
    if (y == 0) return 1ll;
    if (y % 2) return mult(x, bp(x, y - 1));
    ll a = bp(x, y / 2);
    return mult(a, a);
}

int main()
{
    srand(time(0));
    ios_base::sync_with_stdio(0);
    iostream::sync_with_stdio(0);
    ios::sync_with_stdio(0);
    cin.tie(NULL);
    cout.tie(NULL);

//    in("input.txt");
//    out("output.txt");

    cin >> n >> m >> q;

    ans = 0;
    for (i = 1; i <= n; i++)
    {
        r[i] = 1;
    }

    for (i = 1; i <= m; i++)
    {
        c[i] = 1;
    }

    while (q--)
    {
        cin >> cmd >> x >> y;
        if (cmd == 'R')
            r[x] = mult(r[x], y);
        else
            c[x] = mult(c[x], y);
    }

    ll sumc = 0;
    for (i = 1; i <= m; i++) sumc = sum(sumc, c[i]);

    ll sumcc = 0;
    for (i = 2; i <= m; i++) sumcc = sum(sumcc, mult(c[i], i - 1));

    for (i = 1; i <= n; i++)
        ans = sum(ans, mult(r[i], sum(mult(sumc, sum(mult(i - 1, m), 1)), sumcc)));

    cout << ans << el;

}

//  x ^ 2 + y ^ 2 = 1
//  x * a_i + y * b_i
//  a_i = -b_i * tan(alpha)
//  a_i / -b_i = tan(alpha)
//  alpha = atan(a_i / (-b_i))

• Subtask 1: 100 / 100