이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*input
*/
#include <bits/stdc++.h>
#include "gondola.h"
using namespace std;
namespace my_template {
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef pair<ld, ld> pd;
typedef vector<int> vi;
typedef vector<vi> vii;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<vl> vll;
typedef vector<pi> vpi;
typedef vector<vpi> vpii;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
typedef vector<pd> vpd;
typedef vector<bool> vb;
typedef vector<vb> vbb;
typedef std::string str;
typedef std::vector<str> vs;
#define x first
#define y second
#define debug(...) cout<<"["<<#__VA_ARGS__<<": "<<__VA_ARGS__<<"]\n"
const ld PI = 3.14159265358979323846264338327950288419716939937510582097494L;
template<typename T>
pair<T, T> operator+(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x + b.x, a.y + b.y); }
template<typename T>
pair<T, T> operator-(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x - b.x, a.y - b.y); }
template<typename T>
T operator*(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.x + a.y * b.y); }
template<typename T>
T operator^(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.y - a.y * b.x); }
template<typename T>
void print(vector<T> vec, string name = "") {
cout << name;
for (auto u : vec)
cout << u << ' ';
cout << '\n';
}
}
using namespace my_template;
const int MOD = 1000000007;
const ll INF = std::numeric_limits<ll>::max();
const int MX = 100101;
vi kur(250002);
int valid(int n, int inputSeq[])
{
set<int> dabar;
for (int i = 0; i < n; ++i)
{
if (dabar.find(inputSeq[i]) != dabar.end()) return 0;
dabar.insert(inputSeq[i]);
}
set<int> nera;
int did = *(--dabar.end());
for (int i = 0; i < n; ++i)
kur[inputSeq[i]] = i;
for (int i = 1; i < did; ++i)
{
if (dabar.find(i) == dabar.end())
nera.insert(i);
}
while (*(--dabar.end()) != n) {
int c = *(--dabar.end());
int n = *(--nera.end());
inputSeq[kur[c]] = n;
kur[n] = kur[c];
dabar.erase(c);
nera.erase(n);
dabar.insert(n);
}
for (int i = 0; i < n; ++i)
{
if (inputSeq[(kur[1] + i) % n] != i + 1)
return 0;
}
return 1;
}
//----------------------
int replacement(int n, int gondolaSeq[], int replacementSeq[])
{
return -2;
}
//----------------------
int countReplacement(int n, int inputSeq[])
{
return -3;
}
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