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답안 #236790

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
236790 2020-06-03T10:06:06 Z ne4eHbKa Ceste (COCI17_ceste) C++17
64 / 160
 142 ms 9728 KB 
//{ <defines>
#include <bits/stdc++.h>
using namespace std;

//#pragma comment(linker, "/stack:200000000")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
//#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,-O3")

#define fr(i, n) for(int i = 0; i < n; ++i)
#define fo(n) fr(i, n)

#define re return
#define ef else if
#define ifn(x) if(!(x))
#define _  << ' ' <<

#define ft first
#define sd second
#define ve vector
#define pb push_back
#define eb emplace_back

#define sz(x) int((x).size())
#define bnd(x) x.begin(), x.end()
#define clr(x, y) memset((x), (y), sizeof (x))

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef ve<int> vi;

inline ll time() {re chrono :: system_clock().now().time_since_epoch().count();}
mt19937 rnd(time());
mt19937_64 RND(time());

template<typename t> inline void umin(t &a, t b) {a = min(a, b);}
template<typename t> inline void umax(t &a, t b) {a = max(a, b);}

int md = 998244353;

inline int m_add(int&a, int b) {a += b; if(a < 0) a += md; if(a >= md) a -= md; re a;}
inline int m_sum(int a, int b) {a += b; if(a < 0) a += md; if(a >= md) a -= md; re a;}
inline int m_mul(int&a, int b) {re a = 1ll * a * b % md;}
inline int m_prod(int a, int b) {re 1ll * a * b % md;}

int m_bpow(ll A, ll b) {
    int a = A % md;
    ll ans = 1;
    for(ll p = 1ll << 63 - __builtin_clzll(b); p; p >>= 1) {
        (ans *= ans) %= md;
        if(p & b)
            (ans *= a) %= md;
    }
    re ans;
}

//const ld pi = arg(complex<ld>(-1, 0));
//const ld pi2 = pi + pi;
const int oo = 2e9;
const ll OO = 4e18;
//} </defines>
const int N = 105;
const int mx = N * N;

int n, m;
int a[N], b[N], c[N], t[N], f[N][mx];

void solve() {
    cin >> n >> m;
    fo(m) cin >> a[i] >> b[i] >> c[i] >> t[i], --a[i], --b[i];
    clr(f, 127);
    f[0][0] = 0;
    for(int T = 0; T < mx; ++T) {
        fo(n) {
            if(f[i][T] > oo) continue;
            fr(j, m) if(a[j] == i && T + t[j] < mx) umin(f[b[j]][T + t[j]], f[i][T] + c[j]);
            fr(j, m) if(b[j] == i && T + t[j] < mx) umin(f[a[j]][T + t[j]], f[i][T] + c[j]);
        }
    }
    ll ans[n];
    clr(ans, -1);
    fo(n) fr(j, mx) if(f[i][j] < oo) {
        ll p = f[i][j];
        p *= j;
        if(~ans[i] && ans[i] <= p) continue;
        ans[i] = p;
    }
    fo(n) if(i) cout << ans[i] << endl;
}

signed main() {
#ifdef _LOCAL
    freopen("in.txt", "r", stdin);
    int tests; cin >> tests;
    for(int test = 1; test <= tests; ++test) {
		cerr << "case #" << test << endl;
        solve();
        cerr << endl;
    }
#else
//    freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout);
    ios_base :: sync_with_stdio(0); cin.tie(0); cout.tie(0);
    solve();
#endif
    return 0;
}

Compilation message

ceste.cpp: In function 'int m_bpow(ll, ll)':
ceste.cpp:50:26: warning: suggest parentheses around '-' inside '<<' [-Wparentheses]
     for(ll p = 1ll << 63 - __builtin_clzll(b); p; p >>= 1) {
                       ~~~^~~~~~~~~~~~~~~~~~~~

Subtask #1
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 19 ms 4864 KB Output is correct

Subtask #2
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 142 ms 4920 KB Output is correct

Subtask #3
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 87 ms 4856 KB Output is correct

Subtask #4
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 121 ms 4984 KB Output is correct

Subtask #5
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 12 ms 9600 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #6
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 13 ms 9612 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #7
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 13 ms 9600 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #8
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 13 ms 9728 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #9
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 14 ms 9728 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #10
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 13 ms 9728 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -