Submission #233417

#TimeUsernameProblemLanguageResultExecution timeMemory
233417dolphingarlicIslands (IOI08_islands)C++14
76 / 100
618 ms131076 KiB
#include <bits/stdc++.h> #define FOR(i, x, y) for (int i = x; i < y; i++) typedef long long ll; using namespace std; vector<pair<int, ll>> graph[1010101], cycle; ll discarded, ans = 0, cmp_ans, dp[1010101], p[5][1010101]; int cycle_start; bool processed[1010101], visited[1010101], on_cycle[1010101], adding = false; void find_cycle(int node, pair<int, ll> parent = {0, 0}) { if (visited[node]) { cycle_start = node; cycle.push_back({node, 0}); cycle.push_back(parent); adding = true; return; } visited[node] = true; for (pair<int, ll> i : graph[node]) if (i != parent) { find_cycle(i.first, {node, i.second}); if (cycle_start) { if (node == cycle_start) adding = false; if (adding) cycle.push_back(parent); return; } } } void calc_tree(int node, int parent = 0) { processed[node] = true; ll mx = 0, sc = 0; for (pair<int, ll> i : graph[node]) if (i.first != parent && !on_cycle[i.first]) { calc_tree(i.first, node); if (dp[i.first] + i.second > mx) sc = mx, mx = dp[i.first] + i.second; else if (dp[i.first] + i.second > sc) sc = dp[i.first] + i.second; } dp[node] = mx; cmp_ans = max(cmp_ans, mx + sc); } int main() { ios_base::sync_with_stdio(0); cin.tie(0); int n; cin >> n; FOR(i, 1, n + 1) { int v; ll l; cin >> v >> l; graph[i].push_back({v, l}); graph[v].push_back({i, l}); } FOR(i, 1, n + 1) if (!processed[i]) { cycle.clear(); cycle_start = 0; find_cycle(i); discarded = cycle.back().second; cycle.pop_back(); for (pair<int, ll> j : cycle) on_cycle[j.first] = true; cmp_ans = 0; int m = cycle.size(); FOR(j, 1, m) p[0][j] = p[0][j - 1] + cycle[j].second; for (int j = m - 2; ~j; j--) p[1][j] = p[1][j + 1] + cycle[j + 1].second; FOR(j, 0, m) { calc_tree(cycle[j].first); p[2][j] = dp[cycle[j].first] - p[0][j]; p[3][j] = dp[cycle[j].first] + p[0][j]; p[4][j] = dp[cycle[j].first] + p[1][j]; } ll mx = p[2][0]; FOR(j, 1, m) { cmp_ans = max(cmp_ans, p[3][j] + mx); mx = max(mx, p[2][j]); } mx = p[4][m - 1]; for (int j = m - 2; ~j; j--) { cmp_ans = max(cmp_ans, p[3][j] + mx + discarded); mx = max(mx, p[4][j]); } ans += cmp_ans; FOR(j, 0, 5) FOR(k, 0, m) p[j][k] = 0; } cout << ans; return 0; }
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