이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define pii pair<int, int>
#define f first
#define s second
#define pb push_back
#define mp make_pair
#define ll long long
#define ld long double
#define sz(v) int(v.size())
#define all(v) v.begin(), v.end()
using namespace std;
const int N = (int) 1e4 + 7;
const int M = (int) 2e6 + 7;
const int K = 202;
const ll LINF = (ll) 1e18;
const int INF = (int) 1e9 + 7;
const double EPS = (double) 1e-9;
ll dp[N][K], a[N];
int p[N][K];
int n, k;
ll sum(int l, int r) {
return a[r] - a[l - 1];
}
int main() {
#define fn "balls"
#ifdef witch
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#else
// freopen(fn".in", "r", stdin);
// freopen(fn".out", "w", stdout);
#endif
cin >> n >> k;
for (int i = 1; i <= n; i++) {
cin >> a[i];
a[i] += a[i - 1];
}
for (int i = 1; i <= n; i++) {
dp[i][1] = sum(1, i - 1) * sum(i, n);
}
for (int i = 2; i <= k; i++) {
for (int j = i; j <= n; j++) {
for (int t = 1; t < j; t++) {
if (dp[j][i] < dp[t][i - 1] + sum(j, n) * sum(t, j - 1)) {
dp[j][i] = dp[t][i - 1] + sum(j, n) * sum(t, j - 1);
p[j][i] = t;
}
}
}
}
int j = 1;
for (int i = 1; i <= n; i++) {
if (dp[j][k] < dp[i][k]) j = i;
}
cout << dp[j][k] << endl;
vector<int> ans;
while (j > 1 && k > 0) {
ans.pb(j);
j = p[j][k];
k--;
}
reverse(all(ans));
for (auto it : ans) cout << it - 1 << " ";
return 0;
}
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