제출 #232726

#제출 시각아이디문제언어결과실행 시간메모리
232726syyFoehn Phenomena (JOI17_foehn_phenomena)C++17
100 / 100
177 ms14768 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; #define FOR(i, a, b) for(ll i = (ll)a; i <= (ll)b; i++) #define DEC(i, a, b) for(ll i = (ll)a; i >= (ll)b; i--) typedef pair<ll, ll> pi; #define f first #define s second typedef vector<ll> vi; typedef vector<pi> vpi; #define pb push_back #define all(v) v.begin(), v.end() #define fastio ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0) ll n, q, s, t, arr[200005], inc[200005], l, r, x, ans; //up = -s, down = +t ll ft[1000005]; // 1-index ll ls(ll x){ return (x & (-x)); } // N means the largest possible index you need for the fenwick!! Refer to flowering for more. void update(ll l, ll r, ll v){ // Updates from l to r inclusive r++; // Update the difference at r+1 not r for(; l <= n; l += ls(l)) ft[l] += v;// Add v to the diff at l for(; r <= n; r += ls(r)) ft[r] -= v;// Minus v from diff at r+1 } ll query(ll p){ // Returns the element at p ll sum = 0; for(; p; p -= ls(p)) sum += ft[p]; return sum; } int main() { fastio; cin >> n >> q >> s >> t; cin >> arr[0]; FOR(i, 1, n) { cin >> arr[i]; update(i, i, arr[i]); ll pre = ans; if (arr[i] > arr[i-1]) ans -= s * (arr[i] - arr[i-1]); else ans += t * (arr[i-1] - arr[i]); inc[i] = ans - pre; } while (q--) { cin >> l >> r >> x; update(l, r, x); ll nh = query(l), change = 0; if (nh > query(l-1)) change -= s * (nh - query(l-1)); else change += t * (query(l-1) - nh); ans += change - inc[l]; inc[l] = change; if (r != n) { change = 0; nh = query(r); if (query(r+1) > nh) change -= s * (query(r+1) - nh); else change += t * (nh - query(r+1)); ans += change - inc[r+1]; inc[r+1] = change; } cout << ans << "\n"; } }
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