이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
#define FOR(i, a, b) for(ll i = (ll)a; i <= (ll)b; i++)
#define DEC(i, a, b) for(ll i = (ll)a; i >= (ll)b; i--)
typedef pair<ll, ll> pi;
#define f first
#define s second
typedef vector<ll> vi;
typedef vector<pi> vpi;
#define pb push_back
#define all(v) v.begin(), v.end()
#define fastio ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
ll n, q, s, t, arr[200005], inc[200005], l, r, x, ans; //up = -s, down = +t
ll ft[1000005]; // 1-index
ll ls(ll x){
return (x & (-x));
}
// N means the largest possible index you need for the fenwick!! Refer to flowering for more.
void update(ll l, ll r, ll v){ // Updates from l to r inclusive
r++; // Update the difference at r+1 not r
for(; l <= n; l += ls(l)) ft[l] += v;// Add v to the diff at l
for(; r <= n; r += ls(r)) ft[r] -= v;// Minus v from diff at r+1
}
ll query(ll p){ // Returns the element at p
ll sum = 0;
for(; p; p -= ls(p)) sum += ft[p];
return sum;
}
int main() {
fastio; cin >> n >> q >> s >> t;
cin >> arr[0];
FOR(i, 1, n) {
cin >> arr[i];
update(i, i, arr[i]);
ll pre = ans;
if (arr[i] > arr[i-1]) ans -= s * (arr[i] - arr[i-1]);
else ans += t * (arr[i-1] - arr[i]);
inc[i] = ans - pre;
}
while (q--) {
cin >> l >> r >> x;
update(l, r, x);
ll nh = query(l), change = 0;
if (nh > query(l-1)) change -= s * (nh - query(l-1));
else change += t * (query(l-1) - nh);
ans += change - inc[l]; inc[l] = change;
if (r != n) {
change = 0;
nh = query(r);
if (query(r+1) > nh) change -= s * (query(r+1) - nh);
else change += t * (nh - query(r+1));
ans += change - inc[r+1]; inc[r+1] = change;
}
cout << ans << "\n";
}
}
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