제출 #232067

#제출 시각아이디문제언어결과실행 시간메모리
232067AQT철인 이종 경기 (APIO18_duathlon)C++14
41 / 100
184 ms58980 KiB
// Problem : APIO '18 P3 - Duathlon // Contest : DMOJ // URL : https://dmoj.ca/problem/apio18p3 // Memory Limit : 1 MB // Time Limit : 600 ms // Powered by CP Editor (https://github.com/cpeditor/cpeditor) #include <bits/stdc++.h> using namespace std; int N, M; vector<int> graph[100005], cgraph[200005]; vector<pair<int, int>> stk; vector<vector<pair<int, int>>> cmp; int par[200005], dfn[200005], low[200005], t; long long sz[200005], csz[200005]; long long ans; void dfs1(int n){ low[n] = dfn[n] = ++t; int c = 0; for(int e : graph[n]){ if(e == par[n]){ continue; } if(!dfn[e]){ c++; par[e] = n; stk.emplace_back(n, e); dfs1(e); low[n] = min(low[n], low[e]); if((!par[n] && c >= 2) || (par[n] && low[e] >= dfn[n])){ //cout << "enter: " << n << "\n"; pair<int, int> edg = {0, 0}; vector<pair<int, int>> tmp; do{ edg = stk.back(); stk.pop_back(); tmp.push_back(edg); //cout << "indfs: " << edg.first << " " << edg.second << "\n"; } while(edg != make_pair(n, e)); cmp.push_back(tmp); } } else if(dfn[e] < dfn[n]){ low[n] = min(dfn[e], low[n]); stk.emplace_back(n, e); } } } void dfs2(int n){ sz[n] = n <= N; for(int e : cgraph[n]){ if(e != par[n]){ par[e] = n; dfs2(e); sz[n] += sz[e]; } } if(n > N){ csz[n] = cgraph[n].size(); } } void dfs3(int n, long long tot){ if(n > N){ ans -= (csz[n]-1) * (tot-sz[n]) * (tot-sz[n]-1); } for(int e : cgraph[n]){ if(n <= N && e == par[n]){ ans -= (csz[e]-1)*sz[n]*(sz[n]-1); } if(e != par[n]){ dfs3(e, tot); } } } int main(){ cin.sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> N >> M; for(int i = 1; i<=M; i++){ int a, b; cin >> a >> b; graph[a].push_back(b); graph[b].push_back(a); } int C = N; for(int i = 1; i<=N; i++){ if(!dfn[i]){ dfs1(i); if(stk.size()){ cmp.push_back(stk); stk.clear(); } for(auto v : cmp){ ++C; for(auto p : v){ //cout << p.first << " " << p.second << "\n"; cgraph[C].push_back(p.second); cgraph[C].push_back(p.first); } //cout << "\n"; sort(cgraph[C].begin(), cgraph[C].end()); cgraph[C].erase(unique(cgraph[C].begin(), cgraph[C].end()), cgraph[C].end()); for(int n : cgraph[C]){ cgraph[n].push_back(C); } } dfs2(i); dfs3(i, sz[i]); ans += sz[i] * (sz[i]-1) * (sz[i] -2); } } cout << ans << "\n"; }
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