이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<ll,ll> pi;
typedef vector <ll> vi;
typedef vector <pi> vpi;
#define f first
#define s second
#define FOR(i,s,e) for(ll i=s;i<=ll(e);++i)
#define DEC(i,s,e) for(ll i=s;i>=ll(e);--i)
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define lbd(x, y) lower_bound(all(x), y)
#define ubd(x, y) upper_bound(all(x), y)
#define aFOR(i,x) for (auto i: x)
#define mem(x,i) memset(x,i,sizeof x)
#define fast ios_base::sync_with_stdio(false),cin.tie(0)
#define maxn 1000001
typedef long double ld;
#define int ll
int N;
ld X[maxn],Y[maxn];
ld A[maxn],B[maxn];
bool equal(ld a,ld b){
	if (abs(a - b) < 0.000001) return 1;
	else return 0;
}
int32_t main(){
	fast;
	
	cin>>N;
	
	FOR(i,0,N-1) cin>>X[i]>>Y[i];
	
	int fi=-1;
	
	FOR(i,0,N-1){
		if (X[i] - Y[i] >= 0){
			fi = i;
			break;
		}
	}
	if (fi == -1){
		cout<<"No";
		return 0;
	}
	
	rotate(X,X+fi,X+N);
	rotate(Y,Y+fi,Y+N);
	
	B[0] = X[0] - Y[0];
	A[1] = (X[0] - Y[0]) / 2;
	
	FOR(i,1,N - 1){
		B[i] = X[i] - Y[i] + A[i];
		A[(i + 1) % N] = B[i]/2;
	}
	ld z = - B[0] + A[0] - Y[0] + X[0];
	if (z == 0){
		FOR(i,0,N-1){
			if (ll(B[i]) % 2 != 0 || !equal(ll(B[i]),B[i]) || B[i] < 0){
				cout<<"No";
				return 0;
			}
		}
		cout<<"Yes";
		return 0;
	}
	
	ld a = 1;
	FOR(i,1,N) a /= 2;
	
	ld k = 1/z - (a * (1/z));
	k = 1/k;
	
	FOR(i,0,N-1){
		B[i] += k;
		k /= 2;
	}
	//int num = 0;
	FOR(i,0,N-1){
		A[i] = B[(i - 1 + N) % N] / 2;
		
		if (!equal(round(B[i]),B[i]) || (ll)round(B[i]) % 2 != 0 || B[i] < 0 || !equal(round(A[i]),A[i])){
			cout<<"No";
			return 0;
		}
		B[i] = round(B[i]);
		A[i] = round(A[i]);
	}
	
	bool done = 0;
	while (!done){
		done = 1;
		FOR(i,0,N-1){
			ll send = (ll(min(X[i],B[i])) / 2) * 2;
			if (send > 0) done = 0;
			B[i] -= send;
			X[i] -= send;
			X[(i+1) % N] += send / 2;
		}
	}
	
	FOR(i,0,N-1){
		if (X[i] != Y[i]){
			cout<<"No";
			return 0;
		}
	}
			
	cout<<"Yes";
}
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