#include<bits/stdc++.h>
using namespace std;
#define int long long
#define ii pair <int, int>
#define app push_back
#define all(a) a.begin(), a.end()
#define bp __builtin_popcountll
#define ll long long
#define mp make_pair
#define f first
#define s second
#define Time (double)clock()/CLOCKS_PER_SEC
const int N = 107, MOD = 1000 * 1000 * 1000 + 7;
int a[N], l[N], r[N], cntl[N], cntr[N], pw[N];
struct Seg {
ii tree[N << 2];
ii merge(ii a, ii b) {
if (a.f > b.f)
return a;
if (b.f > a.f)
return b;
return mp(a.f, (a.s + b.s) % MOD);
}
void add(int v, int l, int r, int i, ii e) {
if (l == r) {
tree[v] = merge(tree[v], e);
return;
}
int m = (l + r) >> 1;
if (i <= m)
add(v * 2 + 1, l, m, i, e);
else
add(v * 2 + 2, m + 1, r, i, e);
tree[v] = merge(tree[v * 2 + 1], tree[v * 2 + 2]);
}
ii get(int v, int tl, int tr, int l, int r) {
if (tr < l || r < tl)
return mp(0, 0);
if (l <= tl && tr <= r) {
//cout << tl << ' ' << tr << " : " << tree[v].f << ' ' << tree[v].s << endl;
return tree[v];
}
int m = (tl + tr) >> 1;
return merge(get(v * 2 + 1, tl, m, l, r), get(v * 2 + 2, m + 1, tr, l, r));
}
} L, R;
signed main() {
#ifdef HOME
freopen("input.txt", "r", stdin);
#else
#define endl '\n'
ios_base::sync_with_stdio(0); cin.tie(0);
#endif
pw[0] = 1;
for (int i = 1; i < N; ++i)
pw[i] = (pw[i - 1] * 2) % MOD;
int n;
cin >> n;
for (int i = 1; i <= n; ++i)
cin >> a[i];
vector <int> c;
for (int i = 1; i <= n; ++i)
c.app(a[i]);
sort(all(c));
c.resize(unique(all(c)) - c.begin());
for (int i = 1; i <= n; ++i)
a[i] = lower_bound(all(c), a[i]) - c.begin();
int len = 0;
for (int i = n; i; --i) {
tie(l[i], cntl[i]) = L.get(0, 0, N, 0, a[i] - 1);
++l[i];
//cout << i << ' ' << l[i] << ' ' << cntl[i] << endl;
if (l[i] == 1)
cntl[i] = 1;
tie(r[i], cntr[i]) = R.get(0, 0, N, a[i] + 1, N);
++r[i];
if (r[i] == 1)
cntr[i] = 1;
L.add(0, 0, N, a[i], mp(l[i], cntl[i]));
R.add(0, 0, N, a[i], mp(r[i], cntr[i]));
len = max(len, l[i] + r[i] - 1);
}
int ans = 0;
for (int i = 1; i <= n; ++i) {
if (l[i] + r[i] - 1 == len) {
ans += (cntl[i] * cntr[i]) % MOD;
ans %= MOD;
}
}
ans = ans * pw[n - len] % MOD;
cout << len << ' ' << ans << endl;
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
4 ms |
384 KB |
Output is correct |
2 |
Correct |
4 ms |
384 KB |
Output is correct |
3 |
Correct |
5 ms |
384 KB |
Output is correct |
4 |
Correct |
5 ms |
384 KB |
Output is correct |
5 |
Correct |
4 ms |
384 KB |
Output is correct |
6 |
Correct |
5 ms |
384 KB |
Output is correct |
7 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
8 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
9 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
10 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
11 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
12 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
13 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
14 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
15 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
16 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
17 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
18 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
19 |
Runtime error |
5 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |
20 |
Runtime error |
6 ms |
512 KB |
Execution killed with signal 11 (could be triggered by violating memory limits) |