이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
#define in(x) freopen(x, "r", stdin)
#define out(x) freopen(x, "w", stdout)
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("-O3")
#define F first
#define S second
#define pb push_back
#define N +100500
#define M ll(1e9 + 7)
#define sz(x) (int)x.size()
#define re return
#define oo ll(1e18)
#define el '\n'
using namespace std;
//using namespace __gnu_pbds;
//typedef tree <int, null_type, less_equal <int> , rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef long long ll;
typedef long double ld;
ll f[2][101][101];
int a[101][101], i, j, q, nx, p, k, x, y, n, m;
int main()
{
srand(time(0));
ios_base::sync_with_stdio(0);
iostream::sync_with_stdio(0);
ios::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
// in("input.txt");
// out("output.txt");
cin >> n >> m >> x >> y >> k;
for (i = 1; i <= n; i++)
for (j = 1; j <= m; j++) cin >> a[i][j], f[0][i][j] = -1e18;
f[0][x][y] = 0;
for (p = 0; p <= k; p++)
{
nx = (p + 1) % 2;
q = p % 2;
for (i = 1; i <= n; i++)
for (j = 1; j <= m; j++) f[nx][i][j] = -1e18;
for (i = 1; i <= n; i++)
for (j = 1; j <= m; j++)
{
f[nx][i + 1][j] = max(f[nx][i + 1][j], f[q][i][j] + a[i + 1][j]);
f[nx][i - 1][j] = max(f[nx][i - 1][j], f[q][i][j] + a[i - 1][j]);
f[nx][i][j + 1] = max(f[nx][i][j + 1], f[q][i][j] + a[i][j + 1]);
f[nx][i][j - 1] = max(f[nx][i][j - 1], f[q][i][j] + a[i][j - 1]);
}
}
cout << f[k % 2][x][y];
}
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