| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 228529 | Ruxandra985 | Collecting Stamps 3 (JOI20_ho_t3) | C++14 | 5 ms | 384 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define DIMN 210
#define INF 2000000000
using namespace std;
long long v[DIMN] , t[DIMN];
pair <long long , long long> dp[2][DIMN][DIMN];
int main()
{
    FILE *fin = stdin;
    FILE *fout = stdout;
    long long n , l , i , j , curr , poz , timp , urm , sol = 0 , went , j2;
    fscanf (fin,"%lld%lld",&n,&l);
    for (i = 1 ; i <= n ; i++)
        fscanf (fin,"%lld",&v[i]);
    v[n + 1] = l;
    for (i = 1 ; i <= n ; i++)
        fscanf (fin,"%lld",&t[i]);
    for (i = 0 ; i <= n + 1 ; i++){
        for (j = 0 ; j <= n + 1 ; j++){
            dp[0][i][j] = dp[1][i][j] = make_pair(INF , 0);
        }
    }
    dp[1][0][0] = dp[0][0][0] = make_pair(0 , 0);
    for (went = 0 ; went <= n ; went++){
        for (i = 0 ; i <= n && i <= went ; i++){
            j2 = n - (went - i) + 1;
            j = went - i;
            /// se presupune ca dp[0/1][i][j] sunt calculate
            /// pt cazul cu 0
            //if (i == 0 && j == 7)
              //  printf ("a");
            timp = dp[0][i][j].first;
            curr = dp[0][i][j].second;
            /// vreau sa revin in j
            timp = timp + v[i] + l - v[j2];
            poz = v[j2];
            /// sunt inapoi in j, acum o sa ma duc mai departe prin j
            urm = j2;
            while (poz != v[i]){
                timp += poz - v[urm - 1];
                if (t[urm - 1] >= timp)
                    curr++;
                poz = v[urm - 1];
                urm--;
                /// te ai mutat altundeva
                if (dp[1][i][n - urm + 1].first > timp || (dp[1][i][n - urm + 1].first == timp && dp[1][i][n - urm + 1].second < curr)){
                    dp[1][i][n - urm + 1] = make_pair(timp , curr);
                    //if (i == 2 && n - urm + 1 == 4){
                      //  printf ("%lld\n", curr);
                    //}
                }
            }
            /// ----------------------------------------------------------------------
            /// pt cazul cu 1
            timp = dp[1][i][j].first;
            curr = dp[1][i][j].second;
            /// vreau sa revin in i
            timp = timp + v[i] + l - v[j2];
            /// sunt inapoi in i, acum o sa ma duc mai departe prin i
            urm = i;
            poz = v[i];
            while (poz != v[j2]){
                timp += v[urm + 1] - poz;
                if (t[urm + 1] >= timp)
                    curr++;
                poz = v[urm + 1];
                urm++;
                /// te ai mutat altundeva
                if (dp[0][urm][j].first > timp || (dp[0][urm][j].first == timp && dp[0][urm][j].second < curr)){
                    dp[0][urm][j] = make_pair(timp , curr);
                    //if (urm == 2 && j == 7){
                      //  printf ("%lld\n", curr);
                    //}
                }
            }
        }
    }
    for (i = 0 ; i <= n + 1 ; i++){
        for (j = 0 ; j <= n + 1 ; j++){
            sol = max(sol , max(dp[0][i][j].second , dp[1][i][j].second));
            //printf ("0 %lld %lld %lld\n" , i , j , dp[0][i][j].second);
            //printf ("1 %lld %lld %lld\n" , i , j , dp[1][i][j].second);
        }
    }
    fprintf (fout,"%lld",sol);
    return 0;
}
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