이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "holiday.h"
#include <bits/stdc++.h>
#ifdef NON_SUBMIT
#define TEST(n) (n)
#define tout cerr
#else
#define TEST(n) ((void)0)
#define tout cin
#endif
using namespace std;
struct PST
{
int l, r, c;
long long s;
PST() : l(0), r(0), c(0), s(0) {}
};
const int SZ=1<<17;
PST tree[2222222];
int node_cnt, N, s, d, xsz, A[100000], x[100000];
long long ans;
void add_tree(int b, int n, int v, int p, int s=0, int e=SZ-1)
{
int m=(s+e)>>1;
if(s==e) {
tree[p].s=tree[b].s+v;
tree[p].c=tree[b].c+1;
return;
}
if(n<=m) {
tree[node_cnt]=PST();
tree[p].l=node_cnt++;
tree[p].r=tree[b].r;
add_tree(tree[b].l,n,v,tree[p].l,s,m);
}
else {
tree[node_cnt]=PST();
tree[p].r=node_cnt++;
tree[p].l=tree[b].l;
add_tree(tree[b].r,n,v,tree[p].r,m+1,e);
}
tree[p].s=tree[tree[p].l].s+tree[tree[p].r].s;
tree[p].c=tree[tree[p].l].c+tree[tree[p].r].c;
}
int kth(int l, int r, int k)
{
int s=0, e=SZ-1;
while(s<e) {
int m=(s+e)>>1;
if(tree[tree[r].l].c-tree[tree[l].l].c>=k) {
l=tree[l].l;
r=tree[r].l;
e=m;
}
else {
k-=tree[tree[r].l].c-tree[tree[l].l].c;
l=tree[l].r;
r=tree[r].r;
s=m+1;
}
}
return s;
}
long long get_sum(int n1, int n2, int p, int s=0, int e=SZ-1)
{
int m=(s+e)>>1;
if(p==0 || n2<n1 || n2<s || e<n1) return 0;
if(n1<=s && e<=n2) return tree[p].s;
return get_sum(n1,n2,tree[p].l,s,m)+get_sum(n1,n2,tree[p].r,m+1,e);
}
void solve(int s1, int e1, int s2, int e2)
{
int m1=(s1+e1)>>1, m2=-1, k;
long long mx=-1, t;
if(s1>e1) return;
for(int i=s2;i<=e2;i++) if(d>2*(s-m1)+i-s) {
k=kth(m1,i+1,min(d-2*(s-m1)-i+s,i-m1+1));
if((t=get_sum(0,k,i+1)-get_sum(0,k,m1))>mx) {
mx=t;
m2=i;
}
}
if(mx==-1) {
solve(m1+1,e1,s2,e2);
return;
}
ans=max(ans,mx);
solve(s1,m1-1,s2,m2);
solve(m1+1,e1,m2,e2);
}
long long findMaxAttraction(int n, int start, int d, int attraction[])
{
N=n; s=start; ::d=d;
if(d==0) return 0;
for(int i=0;i<N;i++) x[i]=A[i]=attraction[i];
sort(x,x+N);
xsz=unique(x,x+N)-x;
node_cnt=N+1;
for(int i=0;i<N;i++) {
A[i]=lower_bound(x,x+xsz,A[i])-x;
add_tree(i,xsz-1-A[i],x[A[i]],i+1);
}
solve(max(0,s-d+1),s,s,min(s+d-1,N-1));
reverse(A,A+N); s=N-1-s;
node_cnt=N+1;
for(int i=0;i<N;i++) {
tree[i+1]=PST();
add_tree(i,xsz-1-A[i],x[A[i]],i+1);
}
solve(max(0,s-d+1),s,s,min(s+d-1,N-1));
return ans;
}
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