이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
typedef long long ll;
typedef long double ld;
#define INF 2001001001
#define MOD 1000000007
int N,M;
string S;
int dp[1000001][3][3][2];//index, max(L-P), max(P-L), 0 for L
int main()
{
//ios_base::sync_with_stdio(0);cin.tie(0);
//freopen (".in","r",stdin);
//freopen (".out","w",stdout);
cin>>N>>M;
cin>>S;
dp[N][0][0][0]=1;
for (int i=N-1;i>=0;i--){
//adding L
for (int j=0;j<2;j++)
for (int k=0;k<=2;k++)
for (int l=0;l<2;l++){
dp[i][j+1][max(0,k-1)][0]+=dp[i+1][j][k][l];
dp[i][j+1][max(0,k-1)][0]%=M;
}
//adding P
for (int j=0;j<=2;j++)
for (int k=0;k<2;k++)
for (int l=0;l<2;l++){
dp[i][max(0,j-1)][k+1][1]+=dp[i+1][j][k][l];
dp[i][max(0,j-1)][k+1][1]%=M;
}
}
int L_P=0,P_L=0;
int ans=0;
for (int i=0;i<N;i++){
//cout<<"I: "<<i<<endl;
if (S[i]=='P'){
for (int j=0;j<=2;j++)
for (int k=0;k<=2;k++)
if (j+L_P<=2 && k+P_L<=2){
ans+=dp[i][j][k][0];
//cout<<"add "<<dp[i][j][k][0]<<endl;
ans%=M;
}
}
if (S[i]=='L'){
L_P++;
P_L=max(0,P_L-1);
}
else{
P_L++;
L_P=max(0,L_P-1);
}
}
cout<<ans+1<<endl;
return 0;
}
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