Submission #228072

#	Time	Username	Problem	Language	Result	Execution time	Memory
228072		qkxwsm	Bulldozer (JOI17_bulldozer)	C++14	25 / 100	2088 ms	512 KiB

bulldozer

#include <bits/stdc++.h>

using namespace std;

template<class T, class U>
void ckmin(T &a, U b)
{
    if (a > b) a = b;
}

template<class T, class U>
void ckmax(T &a, U b)
{
    if (a < b) a = b;
}

#define MP make_pair
#define PB push_back
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define SZ(x) ((int) (x).size())
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, a, b) for (auto i = (a); i < (b); i++)
#define FORD(i, a, b) for (auto i = (a) - 1; i >= (b); i--)

typedef __int128_t ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<pii> vpi;
typedef vector<pll> vpl;

const int MAXN = 2013;

struct point
{
    int x, y, w;
};

int N;
point arr[MAXN];
long long ans;

void test(ll cx, ll cy)
{
    vpl angs;
    FOR(i, 0, N)
    {
        angs.PB({arr[i].x * cx + arr[i].y * cy, arr[i].w});
    }
    sort(ALL(angs));
    ll sum = 0;
    FOR(i, 0, N)
    {
        sum += angs[i].se;
        if (i != N - 1 && angs[i + 1].fi == angs[i].fi)
        {
            continue;
        }
        ckmax(ans, sum);
        ckmax(sum, 0);
    }
    return;
}

int32_t main()
{
    cout << fixed << setprecision(12);
    cerr << fixed << setprecision(4);
    ios_base::sync_with_stdio(false); cin.tie(0);
    cin >> N;
    FOR(i, 0, N)
    {
        cin >> arr[i].x >> arr[i].y >> arr[i].w;
        ckmax(ans, arr[i].w);
    }
    test(0, 0);
    test(0, 1);
    test(1, 0);
    FOR(i, 0, N)
    {
        FOR(j, i + 1, N)
        {
            ll dy = arr[i].y - arr[j].y, dx = arr[j].x - arr[i].x;
            test(dy, dx);
            test(dy * 200000009 + 1, dx * 200000009);
            test(dy * 200000009 - 1, dx * dy * 200000009);
        }
    }
    cout << ans << '\n';
    return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 20 / 20
• Subtask 3: 0 / 35
• Subtask 4: 0 / 20
• Subtask 5: 0 / 20