Submission #228001

#	Time	Username	Problem	Language	Result	Execution time	Memory
228001		emil_physmath	Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)	C++17	64 / 100	989 ms	262148 KiB

sortbooks

#include <algorithm>
#include <iostream>
#include <bitset>
#include <vector>
using namespace std;

int a[1000'000], w[1000'000];
bitset<1000'000> ans;
int* t[4000'000];
int tans[4000'000], p[4000'000];

void Build(int v, int vl, int vr)
{
    t[v] = new int[vr - vl + 1];
    p[v] = vr - vl;
    if (vl == vr)
    {
        // ans[v] = 0;
        t[v][0] = a[vr];
        return;
    }
    int vm = vl + (vr - vl) / 2;
    Build(v * 2, vl, vm);
    Build(v * 2 + 1, vm + 1, vr);
    merge(t[v * 2], t[v * 2] + vm - vl + 1,
          t[v * 2 + 1], t[v * 2 + 1] + vr - vm,
          t[v]);
    tans[v] = max(tans[v * 2], tans[v * 2 + 1]);
    auto smaller = lower_bound(t[v * 2 + 1], t[v * 2 + 1] + vr - vm, t[v * 2][vm - vl]);
    if (smaller != t[v * 2 + 1])
        tans[v] = max(tans[v], t[v * 2][vm - vl] + *--smaller);
}
struct UPD
{
    int maxAtLeft, q;
};
vector<UPD> upd[4000'000];
int Query(int v, int vl, int vr, int l, int r, int maxAtLeft, int q)
{
    if (l > vr || vl > r)
        return 0;
    if (l <= vl && vr <= r)
    {
        ans[q] = min((bool)ans[q], tans[v] <= w[q]);
        upd[v].push_back(UPD());
        upd[v].back().maxAtLeft = maxAtLeft;
        upd[v].back().q = q;
        return t[v][vr - vl];
    }
    int vm = vl + (vr - vl) / 2;
    maxAtLeft = max(Query(v * 2, vl, vm, l, r, maxAtLeft, q), maxAtLeft);
    maxAtLeft = max(Query(v * 2 + 1, vm + 1, vr, l, r, maxAtLeft, q), maxAtLeft);
    return maxAtLeft;
}
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0); cout.tie(0);
    int n, m;
    cin >> n >> m;
    for (int i = 0; i < n; ++i)
        cin >> a[i];
    Build(1, 0, n - 1);
    for (int i = 0; i < m; ++i)
    {
        ans[i] = 1;
        int l, r;
        cin >> l >> r >> w[i];
        Query(1, 0, n - 1, --l, --r, 0, i);
    }
    for (int v = 0; v < 4 * n; ++v)
    {
        sort(upd[v].begin(), upd[v].end(), [](const UPD& l, const UPD& r) {
             return l.maxAtLeft > r.maxAtLeft;
        });
        for (UPD x: upd[v])
        {
            int maxAtLeft = x.maxAtLeft, q = x.q;
            while (p[v] >= 0 && t[v][p[v]] >= maxAtLeft)
                --p[v];
            if (p[v] >= 0)
                ans[q] = min((bool)ans[q], maxAtLeft + t[v][p[v]] <= w[q]);
        }
    }
    for (int i = 0; i < m; ++i)
        cout << ans[i] << '\n';
}

• Subtask 1: 8 / 8
• Subtask 2: 9 / 9
• Subtask 3: 0 / 13
• Subtask 4: 17 / 17
• Subtask 5: 30 / 30
• Subtask 6: 0 / 23