제출 #227902

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
227902		emil_physmath	Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)	C++17	64 / 100	756 ms	262144 KiB

sortbooks

#include <algorithm>
#include <iostream>
#include <vector>
using namespace std;

vector<int> a;
int w[1000'000], ans[1000'000];
int* t[4000'000];
int tans[4000'000], p[4000'000];

void Build(int v, int vl, int vr)
{
    t[v] = new int[vr - vl + 1];
    p[v] = vr - vl;
    if (vl == vr)
    {
        ans[v] = 0;
        t[v][0] = a[vr];
        return;
    }
    int vm = vl + (vr - vl) / 2;
    Build(v * 2, vl, vm);
    Build(v * 2 + 1, vm + 1, vr);
    merge(t[v * 2], t[v * 2] + vm - vl + 1,
          t[v * 2 + 1], t[v * 2 + 1] + vr - vm,
          t[v]);
    tans[v] = max(tans[v * 2], tans[v * 2 + 1]);
    auto smaller = lower_bound(t[v * 2 + 1], t[v * 2 + 1] + vr - vm, t[v * 2][vm - vl]);
    if (smaller != t[v * 2 + 1])
        tans[v] = max(tans[v], t[v * 2][vm - vl] + *--smaller);
}
struct UPD
{
    int v, maxAtLeft, q;
};
vector<UPD> upd;
int Query(int v, int vl, int vr, int l, int r, int maxAtLeft, int q)
{
    if (l > vr || vl > r)
        return 0;
    if (l <= vl && vr <= r)
    {
        ans[q] = max(ans[q], tans[v]);
        upd.push_back(UPD());
        upd.back().v = v;
        upd.back().maxAtLeft = maxAtLeft;
        upd.back().q = q;
        return t[v][vr - vl];
    }
    int vm = vl + (vr - vl) / 2;
    maxAtLeft = max(Query(v * 2, vl, vm, l, r, maxAtLeft, q), maxAtLeft);
    maxAtLeft = max(Query(v * 2 + 1, vm + 1, vr, l, r, maxAtLeft, q), maxAtLeft);
    return maxAtLeft;
}
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0); cout.tie(0);
    upd.reserve(1000'000 * 20);
    int n, m;
    cin >> n >> m;
    a.resize(n);
    for (int i = 0; i < n; ++i)
        cin >> a[i];
    Build(1, 0, n - 1);
    vector<int>().swap(a);
    for (int i = 0; i < m; ++i)
    {
        ans[i] = 0;
        int l, r;
        cin >> l >> r >> w[i];
        Query(1, 0, n - 1, --l, --r, 0, i);
    }
    sort(upd.begin(), upd.end(), [](const UPD& l, const UPD& r) {
         return l.maxAtLeft > r.maxAtLeft;
    });
    for (UPD x: upd)
    {
        int v = x.v, maxAtLeft = x.maxAtLeft, q = x.q;
        while (p[v] >= 0 && t[v][p[v]] >= maxAtLeft)
            --p[v];
        if (p[v] >= 0)
            ans[q] = max(ans[q], maxAtLeft + t[v][p[v]]);
    }
    for (int i = 0; i < m; ++i)
        cout << (ans[i] <= w[i]) << '\n';
}

• Subtask 1: 8 / 8
• Subtask 2: 9 / 9
• Subtask 3: 0 / 13
• Subtask 4: 17 / 17
• Subtask 5: 30 / 30
• Subtask 6: 0 / 23