제출 #227427

#제출 시각아이디문제언어결과실행 시간메모리
227427dvdg6566Commuter Pass (JOI18_commuter_pass)C++14
100 / 100
842 ms40232 KiB
#include<bits/stdc++.h> using namespace std; typedef long long ll; typedef vector<ll> vi; typedef pair<ll,ll> pi; typedef vector<pi> vpi; typedef long double ld; #define pb emplace_back #define mp make_pair #define lb lower_bound #define ub upper_bound #define ALL(x) x.begin(), x.end() #define SZ(x) (ll)x.size() #define f first #define s second const ll MAXN = 200100; const ll INF = 1e18; const ll MOD = 1e9+7; typedef pair<ll,pi> pip; vector<pip> E; vpi V[MAXN]; ll d1[MAXN]; ll d2[MAXN]; ll N,M,a,b,w; ll S,T,X,Y; priority_queue<pi,vpi,greater<pi>>pq; map<pi,ll> Z; vpi useful; ll ans=INF; void dijkstra(int rt){ memset(d1,-1,sizeof(d1)); d1[rt]=0; pq.push(mp(0,rt)); while (SZ(pq)){ ll n = pq.top().s; ll d =pq.top().f; pq.pop(); if (d1[n]!=d)continue; for (auto v:V[n]){ ll w=d+v.s; if (d1[v.f]!=-1&&d1[v.f]<=w)continue; d1[v.f]=w; pq.push(mp(w,v.f)); } } // cout<<"Distances from node "<<rt<<'\n'; // for (int i=1;i<=N;++i)cout<<d1[i]<<' ';cout<<'\n'; } ll D[300100]; void dijkstra2(int rt){ memset(D,-1,sizeof(D)); D[rt]=0; pq.push(mp(0,rt)); while (SZ(pq)){ ll n = pq.top().s; ll d =pq.top().f; pq.pop(); if (D[n]!=d)continue; ll b=((n-1)/N);n-=b*N; // cerr<<b<<' '<<n<<' '<<d<<'\n'; if (b==0){ // Hvae not gone anywhere for (auto v:V[n]){ ll w=d+v.s; ll c=v.f; if(v.s==0)c=N+v.f; if (D[c]!=-1&&D[c]<=w)continue; D[c]=w; pq.push(mp(w,c)); } }else if (b==1){ for (auto v:V[n]){ ll w=d+v.s; ll c=v.f+2*N; if(v.s==0){c=N+v.f;} if (D[c]!=-1&&D[c]<=w)continue; D[c]=w; pq.push(mp(w,c)); } }else{ for (auto v:V[n]){ ll w=d+v.s; ll c=v.f+2*N; if (v.s==0)continue; if (D[c]!=-1&&D[c]<=w)continue; D[c]=w; pq.push(mp(w,c)); } } } for (int i=0;i<3;++i)if(D[i*N+Y]!=-1)ans=min(ans,D[i*N+Y]); // cout<<'\n'; } int main(){ cin>>N>>M>>S>>T>>X>>Y; swap(X,Y); for (int i=0;i<M;++i){ cin>>a>>b>>w; E.pb(w, mp(a,b)); V[a].pb(b,w); V[b].pb(a,w); } dijkstra(S); for (int i=1;i<=N;++i)d2[i]=d1[i]; dijkstra(T); // d2 is distance from S, d1 is distance from T ll tar = d2[T]; for (auto x:E){ ll a=x.s.f; ll b=x.s.s; ll w=x.f; if (d1[a]+w+d2[b]==tar){ useful.pb(b,a); }else if(d1[b]+w+d2[a]==tar){ useful.pb(a,b); } } for (auto i:useful)V[i.f].pb(i.s,0); dijkstra2(X); for (auto i:useful)V[i.f].pop_back(); for (auto i:useful)V[i.s].pb(i.f,0); dijkstra2(X); cout<<ans<<'\n'; }
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