# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
22654 | 크리콘 B번 문제는 그리디로 풀려요 (#40) | Unifying Values (KRIII5_UV) | C++98 | 226 ms | 24588 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<stdio.h>
#include<vector>
#include<map>
#define ab(a) ((a)<0?-(a):(a))
using namespace std;
typedef long long lld;
const lld mod = 1000000007;
int N, scn;
lld ba[10101], sum[10101], dyt[101][10101], dcn, dap;
map<lld, int> dix, six;
vector<int> sixs[10101];
lld make_dy(lld sm, int p){
int ix = dix[sm];
if(ix>0) return dyt[ix][p];
dix[sm] = ++dcn;
dyt[dcn][N+1]=1;
for(int i=N; i>=p; i--){
int idx = six[sum[i-1] + sm];
if(idx == 0) continue;
for(int j=0; j<sixs[idx].size(); j++){
int k = sixs[idx][j];
if(k < i)break;
dyt[dcn][i] += dyt[dcn][k+1];
}
dyt[dcn][i] %= mod;
}
return dyt[dcn][p];
}
int main(){
scanf("%d", &N);
for(int i=1; i<=N; i++){
scanf("%lld", &ba[i]), sum[i]=sum[i-1]+ba[i];
six[sum[i]] = i;
}
for(int i=N; i>=1; i--){
sixs[six[sum[i]]].push_back(i);
}
for(int i=1; i<=N; i++){
if(sum[N] == 0){
if(sum[i] == 0) dap += make_dy(0, i+1);
}
else{
if(sum[i] == 0)continue;
if(ab(sum[N]) % ab(sum[i]))continue;
if(sum[N] / sum[i] <= 0)continue;
dap += make_dy(sum[i], i+1);
}
}
printf("%lld", (dap+mod-1)%mod);
return 0;
}
Compilation message (stderr)
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