Submission #226389

#	Time	Username	Problem	Language	Result	Execution time	Memory
226389		shahriarkhan	Type Printer (IOI08_printer)	C++14	80 / 100	1100 ms	50228 KiB

printer

#include<bits/stdc++.h>
using namespace std ;

const int maxN = 5e5 + 5 ;

int nex[maxN][26] , ed[maxN] , mark[maxN] , sz ;

vector<char> ans ;

void insert_string(string &s)
{
    int v = 0 , siz = s.size() ;
    for(int i = 0 ; i < siz ; ++i)
    {
        int c = s[i] - 'a' ;
        if(!nex[v][c]) nex[v][c] = ++sz ;
        v = nex[v][c] ;
    }
    ++ed[v] ;
}

void dfs(int ind)
{
    int marked = 0 , in ;
    while(ed[ind]) ans.push_back('P') , --ed[ind] ;
    for(int i = 0 ; i < 26 ; ++i)
    {
        if(mark[nex[ind][i]])
        {
            marked = nex[ind][i] , in = i ;
            continue ;
        }
        if(nex[ind][i])
        {
            char c = 'a' + i ;
            ans.push_back(c) ;
            dfs(nex[ind][i]) ;
        }
    }
    if(marked)
    {
        char c = 'a' + in ;
        ans.push_back(c) ;
        dfs(marked) ;
    }
    if(ind) ans.push_back('-') ;
}

bool cmp(string &s , string &t)
{
    return s.size()<t.size() ;
}

int main()
{
    int n ;
    scanf("%d",&n) ;
    vector<string> vs ;
    for(int i = 0 ; i < n ; ++i)
    {
        string s ;
        cin>>s ;
        vs.push_back(s) ;
    }
    sort(vs.begin(),vs.end(),cmp) ;
    for(int i = 0 ; i < n - 1 ; ++i) insert_string(vs[i]) ;
    int v = 0 , siz = vs[n-1].size() ;
    for(int i = 0 ; i < siz ; ++i)
    {
        int c = vs[n-1][i] - 'a' ;
        if(!nex[v][c]) nex[v][c] = ++sz ;
        v = nex[v][c] ;
        mark[v] = 1 ;
    }
    ++ed[v] ;
    dfs(0) ;
    int siza = ans.size() ;
    while(ans[siza-1]!='P') --siza ;
    printf("%d\n",siza) ;
    for(int i = 0 ; i < siza ; ++i) cout<<ans[i]<<endl ;
    return 0 ;
}

Compilation message (stderr)

printer.cpp: In function 'int main()':
printer.cpp:57:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d",&n) ;
     ~~~~~^~~~~~~~~

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 10 / 10
• Subtask 4: 10 / 10
• Subtask 5: 10 / 10
• Subtask 6: 10 / 10
• Subtask 7: 10 / 10
• Subtask 8: 10 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10