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#include <bits/stdc++.h>
/*
Karya anak bangsa yang paling agung
Author : Yohandi or... bukan..
*/
#define fs first
#define sc second
#define pb push_back
#define eb emplace_back
#define all(a) a.begin(),a.end()
#define lb(a,x) (lower_bound(all(a),x)-a.begin())
#define ub(a,x) (upper_bound(all(a),x)-a.begin())
#define rep(a,x,y) for(int a=(int)x;a<=(int)y;++a)
#define repd(a,x,y,d) for(int a=(int)x;a<=(int)y;a+=d)
#define res(a,x,y) for(int a=(int)x;a>=(int)y;--a)
#define resd(a,x,y,d) for(int a=(int)x;a>=(int)y;a-=d)
// Ordered Set, Ordered Multiset
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define o_set tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update>
#define o_multiset tree<int,null_type,less_equal<int>,rb_tree_tag,tree_order_statistics_node_update>
using namespace __gnu_pbds;
// .order_of_key(x) -> Number of elements less than x
// * .find_by_order(k) -> Kth smallest element (0-based)
// .erase(x) -> Remove all elements equal to x
#pragma GCC optimize("Ofast")
#pragma GCC optimize ("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
using lint=long long;
mt19937 rng(time(NULL));
lint Power(lint A,lint B,lint C){
if(!B) return 1LL;
lint tmp=Power(A,B>>1,C);
return tmp*tmp%C*(B&1?A:1)%C;
}
int T,N,S,K;
int D[1111111];
lint V[1111111];
bool Solve2(){
if(S!=1) return 0;
for(int i=1;i<=N-1;++i)
if(D[i]!=1) return 0;
for(int i=1;i<=N;++i) V[i]+=V[i-1];
pair<lint,int> Ans={-1,0};
for(int i=min(2*K,N);i<=N;++i)
Ans=max(Ans,{V[i]-V[i-min(2*K,N)],i});
cout<<1<<endl;
cout<<Ans.sc-K<<endl;
return 1;
}
bool Solve4(){
if(K!=1) return 0;
for(int i=1;i<=N-1;++i)
if(D[i]!=2) return 0;
for(int i=1;i<=N;++i) V[i]+=V[i-1];
pair<lint,int> Ans={-1,0};
for(int i=S;i<=N;++i)
Ans=max(Ans,{V[i]-V[i-S],i});
cout<<S<<endl;
for(int i=Ans.sc-S+1;i<=Ans.sc;++i)
cout<<i<<((i==Ans.sc)?"\n":" ");
return 1;
}
int main(){
// ios_base::sync_with_stdio(0);
// cin.tie(0); cout.tie(0);
T=1;
// cin>>T;
rep(t,1,T){
cin>>N>>S>>K;
for(int i=1;i<=N-1;++i) cin>>D[i];
for(int i=1;i<=N;++i) cin>>V[i];
if(Solve2()) return 0;
if(Solve4()) return 0;
}
return 0;
}
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