# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
224395 | PedroBigMan | Birmingham (COCI20_birmingham) | C++14 | 166 ms | 30944 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <iostream>
#include <vector>
#include <cmath>
#include <algorithm>
#include <string>
#include <map>
#include <set>
#include <queue>
#include <deque>
using namespace std;
typedef long long int ll;
typedef unsigned long long int ull;
typedef long double ld;
#define REP(i,a,b) for(ll i=a; i<b; i++)
#define pb push_back
#define mp make_pair
#define pl pair<ll,ll>
#define ff first
#define ss second
#define INF 100000000000000000LL
ll insig;
#define In(vecBRO, LENBRO) REP(IBRO,0,LENBRO) {cin>>insig; vecBRO.pb(insig);}
void Out(vector<ll> x) {REP(i,0,x.size()) {cout<<x[i]<<" ";} cout<<endl;}
class Graph
{
public:
ll N;
vector<vector<ll> > adj;
vector<bool> visited; //for DFS/BFS
Graph(vector<vector<ll> > ad)
{
adj=ad; N=adj.size(); REP(i,0,N) {visited.pb(false);}
}
vector<ll> BFS(ll s)
{
vector<ll> distance; REP(i,0,N) {distance.pb(INF);}
REP(i,0,N) {visited[i]=false;}
distance[s]=0; visited[s]=true;
deque<ll> d; d.pb(s); ll cur;
while(!d.empty())
{
cur=d.front(); d.pop_front();
REP(i,0,adj[cur].size())
{
if(!visited[adj[cur][i]])
{
visited[adj[cur][i]]=true;
d.pb(adj[cur][i]);
distance[adj[cur][i]]=distance[cur]+1;
}
}
}
return distance;
}
};
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
ll N,M,Q,K; cin>>N>>M>>Q>>K;
vector<ll> q; In(q,Q); REP(i,0,Q) {q[i]--;}
vector<ll> xx; vector<vector<ll> > adj; REP(i,0,N) {adj.pb(xx);}
pl cur;
REP(i,0,M)
{
cin>>cur.ff>>cur.ss; cur.ff--; cur.ss--;
adj[cur.ff].pb(cur.ss); adj[cur.ss].pb(cur.ff);
}
REP(i,1,q.size())
{
REP(j,0,adj[q[i]].size()) {adj[q[0]].pb(adj[q[i]][j]);}
}
Graph G(adj);
vector<ll> d=G.BFS(q[0]);
vector<ll> ans; REP(i,0,N) {ans.pb(0LL);}
REP(i,0,N)
{
/*ans[i]=(ll) sqrt(K*K+8LL*K*d[i]);
ans[i]+=(K-1LL);
ans[i]/=(2LL*K);
*/
REP(day,0,INF) {if((K*day*(day+1LL))/2LL>=d[i]) {ans[i]=day; break;}}
}
REP(i,0,q.size()) {ans[q[i]]=0LL;}
REP(i,0,N) {cout<<ans[i]<<" ";}
cout<<endl;
return 0;
}
Compilation message (stderr)
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