답안 #223385

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
223385 2020-04-15T08:30:47 Z jamielim Matching (COCI20_matching) C++14
18 / 110
30 ms 25472 KB
#include <bits/stdc++.h>
using namespace std;

int n;
pair<int,int> arr[100005];
pair<int,int> adj[2][100005];
vector<int> al[100005];

struct node{
	int s,e,m,v;
	node *l,*r;
	node(int S,int E){
		s=S;e=E;m=(s+e)/2;v=0;
		if(s!=e){l=new node(s,m);r=new node(m+1,e);}
	}
	void upd(int x,int add){
		if(s==e){v+=add;return;}
		if(x<=m)l->upd(x,add);
		else r->upd(x,add);
		v=l->v+r->v;
	}
	int qry(int x,int y){
		if(s==x&&e==y)return v;
		if(y<=m)return l->qry(x,y);
		if(x>m)return r->qry(x,y);
		return l->qry(x,m)+r->qry(m+1,y);
	}
}*root; //point modify range sum query

bool poss(vector<pair<int,int> > v){
	//check whether the connections here intersect (false) or not (true)
	vector<pair<int,int> > hor,ver[100005];
	for(int i=0;i<(int)v.size();i++){
		if(arr[v[i].first].first==arr[v[i].second].first){
			ver[arr[v[i].first].first].push_back(make_pair(arr[v[i].first].second,arr[v[i].second].second));
		}else{
			int a=arr[v[i].first].first,b=arr[v[i].second].first;
			if(a>b)swap(a,b);
			hor.push_back(make_pair(a,arr[v[i].first].second));hor.push_back(make_pair(b,-arr[v[i].second].second));
		}
	}
	sort(hor.begin(),hor.end());
	root=new node(0,100005);
	int ptr=0;
	for(int i=0;i<100005;i++){
		while(ptr<(int)hor.size()&&hor[ptr].first<=i){
			if(hor[ptr].second>0)root->upd(hor[ptr].second,1);
			else root->upd(-hor[ptr].second,-1);
			ptr++;
		}
		for(int j=0;j<(int)ver[i].size();j++){
			int a=ver[i][j].first,b=ver[i][j].second;
			if(a>b)swap(a,b);
			if(root->qry(a,b)>0){
				return false;
			}
		}
	}
	return true;
}

int main(){
	scanf("%d",&n);
	for(int i=0;i<100005;i++)adj[0][i]=adj[1][i]=make_pair(-1,-1);
	for(int i=0;i<n;i++){
		scanf("%d%d",&arr[i].first,&arr[i].second);
		if(adj[0][arr[i].first].first==-1)adj[0][arr[i].first].first=i;
		else adj[0][arr[i].first].second=i;
		if(adj[1][arr[i].second].first==-1)adj[1][arr[i].second].first=i;
		else adj[1][arr[i].second].second=i;
	}
	for(int i=0;i<n;i++){
		if(adj[0][arr[i].first].second==-1&&adj[1][arr[i].second].second==-1){ //no friends
			printf("NE");return 0;
		}
		if(adj[0][arr[i].first].second!=-1){ //vertical friend
			if(adj[0][arr[i].first].first==i)al[i].push_back(adj[0][arr[i].first].second);
			else al[i].push_back(adj[0][arr[i].first].first);
		}
		if(adj[1][arr[i].second].second!=-1){ //horizontal friend
			if(adj[1][arr[i].second].first==i)al[i].push_back(adj[1][arr[i].second].second);
			else al[i].push_back(adj[1][arr[i].second].first);
		}
		//draw directed edges, the other direction will be drawn by the other person
	}
	//for(int i=0;i<n;i++){for(int j=0;j<(int)al[i].size();j++)printf("%d ",al[i][j]);printf("\n");}
	vector<pair<int,int> > ans;
	//consider "forced" friends (degree 1)
	queue<int> q;
	for(int i=0;i<n;i++){
		if((int)al[i].size()==1)q.push(i);
	}
	while(!q.empty()){
		int cur=q.front();q.pop();
		for(int i=0;i<(int)al[cur].size();i++){ //1 or 0
			int x=al[cur][i];
			if((int)al[x].size()==2){
				if(al[x][0]==cur){
					al[x][0]=al[x][1];
				}
				al[x].pop_back(); //get rid of cur from x friend list
				ans.push_back(make_pair(cur,x));
				//now x not allowed to have friends anymore
				int y=al[x][0];
				if((int)al[y].size()==1){
					printf("NE"); return 0;
					//y has no friends because x is friends with cur
				}else{
					assert((int)al[y].size()==2);
					if(al[y][0]==x)al[y][0]=al[y][1];
					al[y].pop_back();
					q.push(y); //push cur's friend's friend into the queue
				}
			}else if((int)al[x].size()==1){
				ans.push_back(make_pair(cur,x));
			}
			al[x].clear();
		}
		al[cur].clear();
	}
	//for(int i=0;i<n;i++){for(int j=0;j<(int)al[i].size();j++)printf("%d ",al[i][j]);printf("\n");}
	//everything left in al is degree 2, connect these in one direction
	vector<pair<int,int> > ans2;for(int i=0;i<(int)ans.size();i++)ans2.push_back(ans[i]);
	//ans is vertical, ans2 is horizontal. need to check whether things intersect at the end
	for(int i=0;i<n;i++){
		if((int)al[i].size()==0)continue;
		assert((int)al[i].size()==2);
		if(arr[al[i][0]].first==arr[i].first&&al[i][0]<i){
			ans.push_back(make_pair(al[i][0],i));
		}else if(arr[al[i][1]].first==arr[i].first&&al[i][1]<i){
			ans.push_back(make_pair(al[i][1],i));
		}
		if(arr[al[i][0]].second==arr[i].second&&al[i][0]<i){
			ans2.push_back(make_pair(al[i][0],i));
		}else if(arr[al[i][1]].second==arr[i].second&&al[i][1]<i){
			ans2.push_back(make_pair(al[i][1],i));
		}
	}
	if(poss(ans)){
		if(n>40)return 1;
		printf("DA\n");
		for(int i=0;i<(int)ans.size();i++){
			printf("%d %d\n",ans[i].first+1,ans[i].second+1);
		}
	}else if(poss(ans2)){
		if(n>40)return 2;
		printf("DA\n");
		for(int i=0;i<(int)ans2.size();i++){
			printf("%d %d\n",ans2[i].first+1,ans2[i].second+1);
		}
	}else{
		printf("NE");
	}
}

Compilation message

matching.cpp: In function 'int main()':
matching.cpp:63:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d",&n);
  ~~~~~^~~~~~~~~
matching.cpp:66:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d%d",&arr[i].first,&arr[i].second);
   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
# 결과 실행 시간 메모리 Grader output
1 Correct 20 ms 16000 KB Output is correct
2 Correct 18 ms 16000 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 20 ms 16000 KB Output is correct
2 Correct 18 ms 16000 KB Output is correct
3 Correct 17 ms 16000 KB Output is correct
4 Correct 18 ms 16000 KB Output is correct
5 Correct 18 ms 16000 KB Output is correct
6 Correct 28 ms 25344 KB Output is correct
7 Correct 28 ms 25344 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 20 ms 16000 KB Output is correct
2 Correct 18 ms 16000 KB Output is correct
3 Correct 17 ms 16000 KB Output is correct
4 Correct 18 ms 16000 KB Output is correct
5 Correct 18 ms 16000 KB Output is correct
6 Correct 28 ms 25344 KB Output is correct
7 Correct 28 ms 25344 KB Output is correct
8 Correct 18 ms 16000 KB Output is correct
9 Correct 27 ms 25344 KB Output is correct
10 Correct 28 ms 25336 KB Output is correct
11 Correct 30 ms 25472 KB Output is correct
12 Correct 18 ms 16000 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 20 ms 16000 KB Output is correct
2 Correct 18 ms 16000 KB Output is correct
3 Correct 17 ms 16000 KB Output is correct
4 Correct 18 ms 16000 KB Output is correct
5 Correct 18 ms 16000 KB Output is correct
6 Correct 28 ms 25344 KB Output is correct
7 Correct 28 ms 25344 KB Output is correct
8 Correct 18 ms 16000 KB Output is correct
9 Correct 27 ms 25344 KB Output is correct
10 Correct 28 ms 25336 KB Output is correct
11 Correct 30 ms 25472 KB Output is correct
12 Correct 18 ms 16000 KB Output is correct
13 Incorrect 29 ms 25472 KB Output isn't correct
14 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 20 ms 16000 KB Output is correct
2 Correct 18 ms 16000 KB Output is correct
3 Correct 17 ms 16000 KB Output is correct
4 Correct 18 ms 16000 KB Output is correct
5 Correct 18 ms 16000 KB Output is correct
6 Correct 28 ms 25344 KB Output is correct
7 Correct 28 ms 25344 KB Output is correct
8 Correct 18 ms 16000 KB Output is correct
9 Correct 27 ms 25344 KB Output is correct
10 Correct 28 ms 25336 KB Output is correct
11 Correct 30 ms 25472 KB Output is correct
12 Correct 18 ms 16000 KB Output is correct
13 Incorrect 29 ms 25472 KB Output isn't correct
14 Halted 0 ms 0 KB -