# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
222128 | VEGAnn | 새로운 문제 (COCI19_akvizna) | C++14 | 8 ms | 460 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define sz(x) ((int)x.size())
#define pii pair<int,int>
#define ft first
#define sd second
#define MP make_pair
#define all(x) x.begin(),x.end()
#define PB push_back
using namespace std;
typedef long long ll;
typedef long double ld;
const int N = 3010;
const ll OO = 1e18;
const ld E = 1e-9;
vector<int> vc;
ld f[N][N];
int n, k;
pii pr[N][N];
int main(){
ios_base::sync_with_stdio(0); cin.tie(0);
freopen("in.txt","r",stdin);
cin >> n >> k;
for (int i = 0; i <= k; i++)
for (int j = 0; j <= n; j++)
f[i][j] = -1.0;
f[0][n] = 0.0;
for (int i = 0; i < k; i++)
for (int j = 1; j <= n; j++){
if (f[i][j] < -E) continue;
// for (int nw = j; nw > 0; nw--) {
for (int nw = 1; nw <= j; nw++) {
ld ad = f[i][j] + ld(nw) / ld(j);
if (f[i + 1][j - nw] + E < ad) {
f[i + 1][j - nw] = ad;
pr[i + 1][j - nw] = MP(i, j);
}
}
}
int i = k, j = 0;
while (j < n){
vc.PB(j);
pii nt = pr[i][j];
i = nt.ft;
j = nt.sd;
}
vc.PB(n);
reverse(all(vc));
for (int it = 1; it < sz(vc); it++)
cout << vc[it - 1] - vc[it] << " " << it << '\n';
cout << fixed << setprecision(10) << f[k][0];
return 0;
}
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