이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define in(x) freopen(x,"r",stdin)
#define out(x) freopen(x,"w",stdout)
#define F first
#define S second
#define pb push_back
#define M ll(998244353)
#define inf ll(2e9+7)
#define N ll(200500)
#define sz(x) x.size()
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
#define el '\n'
using namespace std;
typedef unsigned long long ull;
typedef long long ll;
typedef long double ld;
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
//using namespace __gnu_pbds;
//typedef tree <ll, null_type, less_equal <ll>, rb_tree_tag, tree_order_statistics_node_update> os;
ld f[3001][3001];
ll n, k, i, j, kol;
int main()
{
// in("input.txt");
// out("output.txt");
ios_base::sync_with_stdio(false);
iostream::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> k;
f[n][0] = 0;
for (i = 1; i <= k; i++) f[n][i] = -1e18;
for (i = n; i > 0; i--)
for (j = 0; j <= k; j++)
for (kol = 1; kol <= i; kol++) f[i - kol][j + 1] = max(f[i - kol][j + 1], f[i][j] + ld(kol) / ld(i));
cout << setprecision(8) << fixed << f[0][k];
}
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