Submission #221527

#	Time	Username	Problem	Language	Result	Execution time	Memory
221527		ryansee	JOIRIS (JOI16_joiris)	C++14	0 / 100	5 ms	384 KiB

joiris

#include "bits/stdc++.h"
using namespace std;

#define FAST ios_base::sync_with_stdio(false); cin.tie(0);
#define pb push_back
#define eb emplace_back
#define ins insert
#define f first
#define s second
#define cbr cerr << "hi\n"
#define mmst(x, v) memset((x), v, sizeof ((x)))
#define siz(x) ll(x.size())
#define all(x) (x).begin(), (x).end()
#define lbd(x,y) (lower_bound(all(x),y)-x.begin())
#define ubd(x,y) (upper_bound(all(x),y)-x.begin())
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());    //can be used by calling rng() or shuffle(A, A+n, rng)
inline long long rand(long long x, long long y) { return (rng() % (y+1-x)) + x; } //inclusivesss
string inline to_string(char c) {string s(1,c);return s;} template<typename T> inline T gcd(T a,T b){ return a==0?llabs(b):gcd(b%a,a); }

typedef long long ll; 
typedef long double ld;
#define FOR(i,s,e) for(ll i=s;i<=ll(e);++i)
#define DEC(i,s,e) for(ll i=s;i>=ll(e);--i)
typedef pair<ll,ll>pi; typedef pair<ll,pi>spi; typedef pair<pi,pi>dpi;

#define LLINF ((long long)1e18)
#define INF int(1e9+1e6)
#define MAXN (106)
ll n,k,A[MAXN],o[MAXN];

int main(){
	FAST
	cin>>n>>k;
	FOR(i,1,n)cin>>A[i],o[i]=A[i];
	auto mod=[&](vector<pi>&v,ll&p){
		ll x=*min_element(A+1,A+n+1);
		FOR(i,1,n)A[i]-=x;
		p -= x, p += k, p %= k;
		while(*max_element(A+1,A+n+1)>=k){
			v.eb(1,min_element(A+1,A+n+1)-A), A[min_element(A+1,A+n+1)-A] += k;
			ll x=*min_element(A+1,A+n+1);
			FOR(i,1,n)A[i]-=x;
			p -= x, p += k, p %= k;
		}
	};
	vector<pi> moves;
	auto can=[&](ll p){
		FOR(i,1,n)A[i]=o[i];
		moves.clear();
		mod(moves,p);
		FOR(i,1,n-k+1) {
			while (A[i]%k != p) {
				moves.eb(0,i); // 0 means horizontal
				FOR(j,i,i+k-1){
					++ A[j];
				}
				mod(moves,p);
			}
		}
		FOR(i,1,n)if(A[i]%k!=p)return 0;
		assert(*max_element(A+1,A+n+1)==0);
		return 1;
	};
	FOR(p,0,k-1) if(can(p)) {
		cout<<moves.size()<<'\n';
		for(auto i:moves) {
			cout<<2-i.f<<' '<<i.s<<'\n';
		}
		return 0;
	}
	cout<<"-1\n";
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 15
• Subtask 3: 0 / 15
• Subtask 4: 0 / 55