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답안 #220075

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
220075 2020-04-06T22:55:45 Z tatyam Pyramid Base (IOI08_pyramid_base) C++17
27 / 100
 370 ms 27812 KB 
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int INF = 0x3fffffff;
template<class T, class U> bool chmin(T& a, const U& b){ if(a > b){ a = b; return 1; } return 0; }
#define rep(b) for(ll i = 0; i < b; i++)
#define each(i,a) for(auto&& i : a)
#define all(a) begin(a), end(a)
 
ll seg[800000], lazy[800000];
struct SegTree{
    int n;
    SegTree(int n): n(n){}
    inline ll get() const {
        return seg[1];
    }
    inline void add(int l, int r, int val){
        if(l < 0) l = 0;
        if(r > n) r = n;
        l += n;
        r += n;
        int L = l, R = r;
        for(; L < R; L /= 2, R /= 2){
            if(L & 1){
                seg[L] += val;
                lazy[L++] += val;
            }
            if(R & 1){
                seg[--R] += val;
                lazy[R] += val;
            }
        }
        r--;
        while(l /= 2) seg[l] = min(seg[l * 2], seg[l * 2 | 1]) + lazy[l];
        while(r /= 2) seg[r] = min(seg[r * 2], seg[r * 2 | 1]) + lazy[r];
    }
    inline void clear(int l, int r){
        if(l < 0) l = 0;
        if(r > n) r = n;
        l += n;
        r += n;
        int L = l, R = r;
        for(; L < R; L /= 2, R /= 2){
            if(L & 1){
                seg[L] = 0;
                lazy[L++] = 0;
            }
            if(R & 1){
                seg[--R] = 0;
                lazy[R] = 0;
            }
        }
        r--;
        while(l /= 2) seg[l] = 0;
        while(r /= 2) seg[r] = 0;
    }
};
int main(){
    int m, n, b, p;
    scanf("%d %d %d %d", &m, &n, &b, &p);
    using tuplis = array<int, 4>;
    vector<tuplis> in, out;
    rep(p){
        int x1, y1, x2, y2, c;
        scanf("%d %d %d %d %d", &x1, &y1, &x2, &y2, &c);
        x1--; y1--;
        in.push_back({x1, y1, y2, c});
        out.push_back({x2, y1, y2, -c});
    }
    sort(all(in));
    sort(all(out));
    in.push_back({INF, 0, 0, 0});
    out.push_back({INF, 0, 0, 0});
    auto check = [&](int x) -> bool {
        x--;
        SegTree seg(n - x);
        int i1 = 0, i2 = 0, at = 0;
        bool ans = 0;
        while(at < m - x){
            while(in[i1][0] - x <= at){
                seg.add(in[i1][1] - x, in[i1][2], in[i1][3]);
                i1++;
            }
            while(out[i2][0] <= at){
                seg.add(out[i2][1] - x, out[i2][2], out[i2][3]);
                i2++;
            }
            if(seg.get() <= b){
                ans = 1;
                break;
            }
            at = min(in[i1][0] - x, out[i2][0]);
        }
        for(; i2 < i1; i2++) seg.clear(out[i2][1] - x, out[i2][2]);
        return ans;
    };
    int ok = 0, ng = min(n, m) + 1;
    while(ng - ok > 1){
        ll cen = (ok + ng) / 2;
        if(check(cen)) ok = cen;
        else ng = cen;
    }
    cout << ok << endl;
}

Compilation message

pyramid_base.cpp: In function 'int main()':
pyramid_base.cpp:60:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d %d %d", &m, &n, &b, &p);
     ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
pyramid_base.cpp:65:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d %d %d %d %d", &x1, &y1, &x2, &y2, &c);
         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 384 KB Output is correct

Subtask #2
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 4 ms 384 KB Output isn't correct

Subtask #3
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 384 KB Output is correct

Subtask #4
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 768 KB Output is correct

Subtask #5
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 13 ms 3200 KB Output is correct

Subtask #6
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 7 ms 1024 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #7
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 6 ms 640 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #8
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 16 ms 896 KB Output is correct
2 Correct 32 ms 1024 KB Output is correct
3 Incorrect 29 ms 1024 KB Output isn't correct

Subtask #9
7.0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 97 ms 3700 KB Output is correct
2 Correct 151 ms 4596 KB Output is correct
3 Correct 125 ms 4472 KB Output is correct

Subtask #10
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 23 ms 3060 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #11
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 28 ms 3436 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #12
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 34 ms 3820 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #13
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 191 ms 15820 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #14
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 274 ms 21796 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #15
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 370 ms 27812 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -