제출 #219132

#제출 시각아이디문제언어결과실행 시간메모리
219132mode149256Unscrambling a Messy Bug (IOI16_messy)C++14
100 / 100
7 ms512 KiB
/*input */ #include <bits/stdc++.h> #include "messy.h" using namespace std; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll, ll> pl; typedef pair<ld, ld> pd; typedef vector<int> vi; typedef vector<vi> vii; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<vl> vll; typedef vector<pi> vpi; typedef vector<vpi> vpii; typedef vector<pl> vpl; typedef vector<cd> vcd; typedef vector<pd> vpd; typedef vector<bool> vb; typedef vector<vb> vbb; typedef std::string str; typedef std::vector<str> vs; #define x first #define y second #define debug(...) cout<<"["<<#__VA_ARGS__<<": "<<__VA_ARGS__<<"]\n" const int MOD = 1000000007; const ll INF = std::numeric_limits<ll>::max(); const int MX = 100101; const ld PI = 3.14159265358979323846264338327950288419716939937510582097494L; template<typename T> pair<T, T> operator+(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x + b.x, a.y + b.y); } template<typename T> pair<T, T> operator-(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x - b.x, a.y - b.y); } template<typename T> T operator*(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.x + a.y * b.y); } template<typename T> T operator^(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.y - a.y * b.x); } template<typename T> void print(vector<T> vec, string name = "") { cout << name; for (auto u : vec) cout << u << ' '; cout << '\n'; } using bt = bitset<128>; int N; void add(bt b) { str s = b.to_string(); reverse(s.begin(), s.end()); s.resize(N); // cout << "add: " << s << '\n'; add_element(s); } bool check(bt b) { str s = b.to_string(); reverse(s.begin(), s.end()); s.resize(N); bool ans = check_element(s); // cout << "check: " << s << " ans: " << (ans ? "true" : "false" ) << '\n'; return ans; } str print(bt b) { str s = b.to_string(); reverse(s.begin(), s.end()); s.resize(N); return s; } void add_all(bt space, int k) { // cout << space.to_string() << " " << k << '\n'; if (k == 1) return; bt curr = ~space; int pr = k; k /= 2; bt left, right; for (int i = 0; i < N; ++i) { if (space[i] and k) { curr[i] = 1; add(curr); curr[i] = 0; k--; left[i] = 1; } else if(space[i] and !k) { right[i] = 1; } } // cout << "left: " << print(left) << " right: " << print(right) << '\n'; add_all(left, pr / 2); add_all(right, pr / 2); } vi P; void finish(bt space, int k, bt kur) { // cout << "space: " << print(space) << " k = " << k << " kur: " << print(kur) << '\n'; if (k == 1) { int i = 0; while (!space[i]) i++; int j = 0; while (!kur[j]) j++; // printf("i = %d, j = %d\n", i, j); // P[i] = j; P[j] = i; return; } bt curr = ~kur; bt leftKur; bt rightKur; int pr = k; k /= 2; for (int i = 0; i < N; ++i) { if (kur[i]) { curr[i] = 1; if (check(curr)) { leftKur[i] = 1; // leftKur |= (curr & kur); } else { rightKur[i] = 1; // rightKur |= (curr & kur); } curr[i] = 0; } } bt left, right; for (int i = 0; i < N; ++i) { if (space[i] and k) { left[i] = 1; k--; } else if(space[i] and !k){ right[i] = 1; } } finish(left, pr / 2, leftKur); finish(right, pr / 2, rightKur); } std::vector<int> restore_permutation(int n, int w, int r) { N = n; bt curr; curr.set(); add_all(curr, N); compile_set(); P = vi(N); finish(curr, N, curr); return P; }
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