제출 #218902

#제출 시각아이디문제언어결과실행 시간메모리
218902eggag32Putovanje (COCI20_putovanje)C++17
0 / 110
211 ms24820 KiB
#pragma GCC optimize ("O3") #pragma GCC target ("sse4") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef vector<int> vi; typedef pair<int, int> pi; #define debug(x) cerr << #x << ": " << x << endl; #define debug2(x, y) debug(x) debug(y); #define repn(i, a, b) for(int i = (int)(a); i < (int)(b); i++) #define rep(i, a) for(int i = 0; i < (int)(a); i++) #define all(v) v.begin(), v.end() #define mp make_pair #define pb push_back #define lb lower_bound #define ub upper_bound #define fi first #define se second #define sq(x) ((x) * (x)) template<class T> T gcd(T a, T b){ return ((b == 0) ? a : gcd(b, a % b)); } int vis1[200005]; //don't forget to initialize to zeroes vi ord; //don't forget to reverse in the end vi g[200005]; void dfs0(int cur){ vis1[cur] = 1; for(int x : g[cur]) if(!vis1[x]) dfs0(x); ord.pb(cur); } int main(){ ios_base::sync_with_stdio(false); cin.tie(0); //freopen("input.in", "r", stdin); //freopen("output.out", "w", stdout); int n; cin >> n; map<pi, pi> m; rep(i, n - 1){ int a, b, c, d; cin >> a >> b >> c >> d; a--, b--; g[a].pb(b); g[b].pb(a); m[mp(a, b)] = mp(c, d); m[mp(b, a)] = mp(c, d); } memset(vis1, 0, sizeof(vis1)); rep(i, n) if(!vis1[i]) dfs0(i); reverse(all(ord)); vi pos(n, 0); rep(i, n) pos[ord[i]] = i; vi cnt(n + 5, 0); repn(i, 1, n){ //we go from 0 -> 1, 1 -> 2, 2 -> 3 if(pos[i - 1] < pos[i]) cnt[pos[i - 1] + 1]++, cnt[pos[i] + 1]--; else cnt[pos[i] + 1]++, cnt[pos[i - 1] + 1]--; } partial_sum(all(cnt), cnt.begin()); ll ans = 0; repn(i, 1, n){ pi x = m[mp(ord[i - 1], ord[i])]; ans += min(cnt[i] * x.fi, x.se); } cout << ans << endl; return 0; } /* Things to look out for: - Integer overflows - Array bounds - Special cases Be careful! */
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...