제출 #218656

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
218656		ryansee	Just Long Neckties (JOI20_ho_t1)	C++14	0 / 100	5 ms	384 KiB

ho_t1

#include "bits/stdc++.h"
using namespace std;

#define FAST ios_base::sync_with_stdio(false); cin.tie(0);
#define pb push_back
#define eb emplace_back
#define ins insert
#define f first
#define s second
#define cbr cerr << "hi\n"
#define mmst(x, v) memset((x), v, sizeof ((x)))
#define siz(x) ll(x.size())
#define all(x) (x).begin(), (x).end()
#define lbd(x,y) (lower_bound(all(x),y)-x.begin())
#define ubd(x,y) (upper_bound(all(x),y)-x.begin())
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());    //can be used by calling rng() or shuffle(A, A+n, rng)
inline long long rand(long long x, long long y) { return (rng() % (y+1-x)) + x; } //inclusivesss
string inline to_string(char c) {string s(1,c);return s;} template<typename T> inline T gcd(T a,T b){ return a==0?llabs(b):gcd(b%a,a); }

typedef long long ll; 
typedef long double ld;
#define FOR(i,s,e) for(ll i=s;i<=ll(e);++i)
#define DEC(i,s,e) for(ll i=s;i>=ll(e);--i)
typedef pair<ll,ll>pi; typedef pair<ll,pi>spi; typedef pair<pi,pi>dpi;

#define LLINF ((long long)1e18)
#define INF int(1e9+1e6)
#define MAXN (300006)
ll n,B[MAXN],ans[MAXN];
pi A[MAXN];
int main(){
	FAST
	cin>>n;
	FOR(i,1,n+1)cin>>A[i].f,A[i].s=i;
	FOR(i,1,n)cin>>B[i];
	sort(B+1,B+n+1), sort(A+1,A+n+2);
	ll p_mx=-LLINF;
	multiset<ll> ms;
	ms.ins(-LLINF);
	FOR(i,1,n)ms.ins(llabs(B[i]-A[i+1].f));
	ans[A[1].s]=*--ms.end();
	FOR(i,2,n+1){
		ms.erase(ms.find(llabs(B[i-1]-A[i].f)));
		p_mx=max(p_mx,llabs(A[i-1].f-B[i-1]));
		ans[A[i].s]=max(p_mx,*--ms.end());
	}
	FOR(i,1,n+1)cout<<ans[i]<<' ';cout<<'\n';
}

컴파일 시 표준 에러 (stderr) 메시지

ho_t1.cpp: In function 'int main()':
ho_t1.cpp:22:20: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
 #define FOR(i,s,e) for(ll i=s;i<=ll(e);++i)
                    ^
ho_t1.cpp:47:2: note: in expansion of macro 'FOR'
  FOR(i,1,n+1)cout<<ans[i]<<' ';cout<<'\n';
  ^~~
ho_t1.cpp:47:32: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
  FOR(i,1,n+1)cout<<ans[i]<<' ';cout<<'\n';
                                ^~~~

• Subtask 1: 0 / 1
• Subtask 2: 0 / 8
• Subtask 3: 0 / 91