/// macar elimin ideile proaste
#include <bits/stdc++.h>
#define DIM 5010
#define INF 2000000000
using namespace std;
vector <int> v[DIM],L[DIM];
int f[DIM],s[DIM],viz[DIM],g[DIM];
deque <int> c;
int n,i,j,nr,x;
void dfs (int nod, int tata){
s[nod] = viz[nod] = 1;
for (auto vecin : L[nod])
if (vecin != tata){
dfs (vecin,nod);
s[nod] += s[vecin];
}
}
int main (){
//ifstream cin ("date.in");
// ofstream cout ("date.out");
cin>>n;
for (i=1;i<=n;i++){
cin>>nr;
for (j=1;j<=nr;j++){
cin>>x;
v[x].push_back(i);
g[i]++;
}
}
/// mereu trb sa leg un nod de unul cat mai sus
for (i=1;i<=n;i++)
if (!g[i]){
c.push_back(i);
f[i] = 1;
}
if (!c.empty()){ /// am deja radacinile obligatorii
c.push_back(i);
f[i] = 1;
for (j=1;j<=n;j++)
if (!g[j] && j != i){
c.push_back(j);
f[j] = 1;
}
while (!c.empty()){
int nod = c.front();
c.pop_front();
for (auto vecin : v[nod]){
if (!f[vecin]){
L[nod].push_back(vecin);
L[vecin].push_back(nod);
f[vecin] = 1;
c.push_back(vecin);
}}}
for (i=1;i<=n;i++)
if (!g[i])
dfs (i,0);
int sum = 0;
for (i=1;i<=n;i++)
sum += s[i];
cout<<sum;
return 0;
}
/// trb sa am un singur arbore??
int sol = INF;
for (i=1;i<=n;i++){ /// aleg o radacina
c.clear();
memset (f,0,sizeof f);
memset (s,0,sizeof s);
memset (viz,0,sizeof viz);
for (j=1;j<=n;j++)
L[j].clear();
c.push_back(i);
f[i] = 1;
while (!c.empty()){
int nod = c.front();
c.pop_front();
for (auto vecin : v[nod]){
if (!f[vecin]){
L[nod].push_back(vecin);
L[vecin].push_back(nod);
f[vecin] = 1;
c.push_back(vecin);
}}}
dfs (i,0);
/*for (j=1;j<=n;j++)
if (!viz[j])
dfs (j,0);
*/
int sum = 0, ok = 1;
for (j=1;j<=n;j++){
sum += s[j];
if (!s[j])
ok = 0;
}
if (ok) /// daca am toate nodurile
sol = min (sol,sum);
}
cout<<sol;
return 0;
}
