답안 #216523

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
216523 2020-03-27T12:52:33 Z vonatlus Trol (COCI19_trol) C++14
30 / 50
1000 ms 384 KB
/// wa ^3^

#pragma GCC optimize("O3")

#include<bits/stdc++.h>
                           
#define x first
#define y second
#define pb push_back
#define sz(x) (int) x.size()
 
using namespace std;
 
using ll = long long;
using pii = pair<int, int>;                                   

const int MOD = 1e9 + 7;
const int INF32 = 1e9 + 1e2;

template<typename T> istream 
&operator>>(istream &a, vector<T> &v) { 
for (auto& x : v) a >> x; return a; }

void stndrtn() {
#ifdef accepted
    freopen(".in", "r", stdin);
#endif        
}

const bool flag = 0;

int f(ll x) {
    int sum = 0;
    for (; x; x /= 10ll)
        sum += x%10;
    if (sum > 9)
        sum = f(sum);
    return sum;
}

void maincode() {
    int q;
    cin >> q;
    for (ll l, r; q--;) {
        cin >> l >> r;
        int sum = 0;
        for (ll i = l; i <= r; ++i)
            sum += f(i);
        cout << sum << "\n";
    }    
}

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(nullptr), stndrtn();
    int ts = 1;
    if (flag) 
        cin >> ts;
    while (ts--)
        maincode(); 
    return 0;
}

Compilation message

trol.cpp: In function 'std::istream& operator>>(std::istream&, std::vector<_Tp>&)':
trol.cpp:22:1: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
 for (auto& x : v) a >> x; return a; }
 ^~~
trol.cpp:22:27: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
 for (auto& x : v) a >> x; return a; }
                           ^~~~~~
# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 384 KB Output is correct
2 Correct 6 ms 384 KB Output is correct
3 Correct 7 ms 384 KB Output is correct
4 Execution timed out 1080 ms 384 KB Time limit exceeded
5 Execution timed out 1092 ms 384 KB Time limit exceeded