제출 #213164

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
213164		SorahISA	Palembang Bridges (APIO15_bridge)	C++17	0 / 100	5 ms	512 KiB

bridge

// #pragma GCC target("avx2")
#pragma GCC optimize("O3", "unroll-loops")
 
// #include <bits/extc++.h>
// using namespace __gnu_pbds;
 
#include <bits/stdc++.h>
using namespace std;
 
#define int long long
#define double long double
// template <typename T>
// using pbds_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
using pii = pair<int, int>;
template<typename T>
using prior = priority_queue<T, vector<T>, greater<T>>;
template<typename T>
using Prior = priority_queue<T>;
 
#define X first
#define Y second
#define ALL(x) (x).begin(), (x).end()
#define eb emplace_back
#define pb push_back
 
#define fastIO() ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#define RANDOM() random_device __rd; \
                 mt19937 __gen = mt19937(__rd()); \
                 uniform_int_distribution<int> __dis(0, 1); \
                 auto rnd = bind(__dis, __gen);
 
const int INF = 1E18;
const int mod = 1E9 + 7;

struct Citizen {
    char p, q;
    int s, t;
    
    void Read() {
        cin >> p >> s >> q >> t;
    }
};

int32_t main() {
    fastIO();
    
    int k, n, ans = 0;
    cin >> k >> n;
    
    vector<Citizen> v;
    for (int i = 0; i < n; ++i) {
        Citizen tmp; tmp.Read();
        if (tmp.s > tmp.t) swap(tmp.s, tmp.t);
        ans += tmp.t - tmp.s;
        if (tmp.p != tmp.q) ++ans, v.eb(tmp);
    }
    n = v.size();
    
    if (k == 1) {
        vector<int> p;
        for (int i = 0; i < n; ++i) p.eb(v[i].s), p.eb(v[i].t); sort(ALL(p));
        
        int midP = p[n];
        for (int i = 0; i < n; ++i) {
            if (midP < v[i].s) ans += 2 * (v[i].s - midP);
            if (v[i].t < midP) ans += 2 * (midP - v[i].t);
        }
        
        cout << ans << "\n";
        
        return 0;
    }
    
    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

bridge.cpp: In function 'int32_t main()':
bridge.cpp:61:9: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
         for (int i = 0; i < n; ++i) p.eb(v[i].s), p.eb(v[i].t); sort(ALL(p));
         ^~~
bridge.cpp:61:65: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
         for (int i = 0; i < n; ++i) p.eb(v[i].s), p.eb(v[i].t); sort(ALL(p));
                                                                 ^~~~

• Subtask 1: 0 / 8
• Subtask 2: 0 / 14
• Subtask 3: 0 / 9
• Subtask 4: 0 / 32
• Subtask 5: 0 / 37