제출 #211308

#제출 시각아이디문제언어결과실행 시간메모리
211308SorahISAArranging Shoes (IOI19_shoes)C++17
100 / 100
794 ms31864 KiB
#include "shoes.h" // #pragma GCC target("avx2") #pragma GCC optimize("O3", "unroll-loops") // #include <bits/extc++.h> // using namespace __gnu_pbds; #include <bits/stdc++.h> using namespace std; #define int long long // template <typename T> // using pbds_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; using pii = pair<int, int>; template<typename T> using prior = priority_queue<T, vector<T>, greater<T>>; template<typename T> using Prior = priority_queue<T>; #define X first #define Y second #define eb emplace_back #define pb push_back #define fastIO() ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) #define RANDOM() random_device __rd; \ mt19937 __gen = mt19937(__rd()); \ uniform_int_distribution<int> __dis(0, 1); \ auto rnd = bind(__dis, __gen); const int INF = 1E18; const int mod = 1E9 + 7; const int maxn = 1 << 18; vector<int> BIT(maxn, 0); void Add(int idx) {while (idx < maxn) ++BIT[idx], idx += idx&-idx;} int Sum(int idx, int ans = 0) {while (idx) ans += BIT[idx], idx -= idx&-idx; return ans;} int count_swaps(vector<int32_t> _S) { vector<int> S; for (auto x : _S) S.eb(x); int n = S.size() / 2, ans = 0; map<int, int> trans; map<int, pii> place; vector<pii> pairs; set<int> appear; for (int i = 0, now = S[i]; i < 2*n; now = S[++i]) { if (!trans[now]) trans[now] = S[i]; S[i] = trans[now]; if (appear.count(S[i])) S[i] += (S[i] > 0 ? n : -n); appear.insert(S[i]), trans[now] = S[i]; } // for (auto x : S) cout << x << ", "; appear.clear(), trans.clear(); for (int i = 0; i < 2*n; ++i) { if (S[i] > 0 and !appear.count(-S[i])) ++ans; appear.insert(S[i]); S[i] = abs(S[i]); } for (int i = 0; i < 2*n; ++i) { if (place[S[i]].first) place[S[i]].second = i + 1; else place[S[i]].first = i + 1; } // for (auto x : place) cout << x.Y.X << ", " << x.Y.Y << "\n"; for (auto x : place) pairs.eb(x.Y.X, x.Y.Y); sort(pairs.begin(), pairs.end()); for (auto pl : pairs) { Add(pl.X), Add(pl.Y), ans += pl.Y - Sum(pl.Y); } return ans; }
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