이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<cstdio>
#include<algorithm>
#define mod 1000000007
using namespace std;
const int MXM = 2e5;
typedef long long ll;
int n, m, idx[MXM + 2], sz=1;
pair<int, int> p[MXM];
struct st {
int s, a = 1, b;
}tree[MXM * 4];
void f(int h, int a, int b) {
tree[h].a = (ll)tree[h].a*a%mod;
tree[h].b = ((ll)tree[h].b*a + b) % mod;
tree[h].s = ((ll)tree[h].s*a + b) % mod;
}
void update(int h, int l, int r, int gl, int gr, int a, int b) {
if (r < gl || gr < l) return;
if (gl <= l&&r <= gr) f(h, a, b);
else {
f(h * 2 + 1, tree[h].a, tree[h].b);
f(h * 2 + 2, tree[h].a, tree[h].b);
tree[h].a = 1;
tree[h].b = 0;
update(h * 2 + 1, l, (l + r) / 2, gl, gr, a, b);
update(h * 2 + 2, (l + r) / 2 + 1, r, gl, gr, a, b);
tree[h].s = ((ll)(tree[h * 2 + 1].s + tree[h * 2 + 2].s)*tree[h].a + tree[h].b) % mod;
}
}
int query(int h, int l, int r, int gl, int gr) {
if (r < gl || gr < l) return 0;
if (gl <= l&&r <= gr) return tree[h].s;
return (query(h * 2 + 1, l, (l + r) / 2, gl, gr) + query(h * 2 + 2, (l + r) / 2 + 1, r, gl, gr)) % mod;
}
int main() {
scanf("%d%d", &n, &m);
idx[sz++] = n;
for (int i = 0; i < m; i++) scanf("%d%d", &p[i].first, &p[i].second), idx[sz++] = p[i].second;
sort(p, p + m);
sort(idx, idx + sz);
sz = unique(idx, idx + sz) - idx;
update(0, 0, sz - 1, 0, 0, 1, 1);
for (int i = 0; i < m; i++) {
int l = lower_bound(idx, idx + sz, p[i].first - 1) - idx,
r = lower_bound(idx, idx + sz, p[i].second) - idx;
update(0, 0, sz - 1, r, r, 1, query(0, 0, sz - 1, l, r));
update(0, 0, sz - 1, r + 1, sz - 1, 2, 0);
}
printf("%d", query(0, 0, sz - 1, sz - 1, sz - 1));
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
rail.cpp: In function 'int main()':
rail.cpp:36:26: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d%d", &n, &m);
^
rail.cpp:38:98: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
for (int i = 0; i < m; i++) scanf("%d%d", &p[i].first, &p[i].second), idx[sz++] = p[i].second;
^
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