/*input
*/
#include <bits/stdc++.h>
#include "grader.h"
using namespace std;
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef pair<ld, ld> pd;
typedef vector<int> vi;
typedef vector<vi> vii;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<vl> vll;
typedef vector<pi> vpi;
typedef vector<vpi> vpii;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
typedef vector<pd> vpd;
typedef vector<bool> vb;
typedef vector<vb> vbb;
typedef std::string str;
typedef std::vector<str> vs;
#define x first
#define y second
#define debug(...) cout<<"["<<#__VA_ARGS__<<": "<<__VA_ARGS__<<"]\n"
const int MOD = 1000000007;
const ll INF = std::numeric_limits<ll>::max();
const int MX = 100101;
const ld PI = 3.14159265358979323846264338327950288419716939937510582097494L;
template<typename T>
pair<T, T> operator+(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x + b.x, a.y + b.y); }
template<typename T>
pair<T, T> operator-(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x - b.x, a.y - b.y); }
template<typename T>
T operator*(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.x + a.y * b.y); }
template<typename T>
T operator^(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.y - a.y * b.x); }
template<typename T>
void print(vector<T> vec, string name = "") {
cout << name;
for (auto u : vec)
cout << u << ' ';
cout << '\n';
}
//Guess
int HC(int N) {
int l = 1;
int r = N;
int last = 1;
Guess(1);
while (l < r) {
printf("l = %d, r = %d, last = %d\n", l, r, last);
int mid = (l + r) / 2;
int ans;
if (last == r) {
ans = Guess(l);
last = l;
if (ans == 0) return (l + r) / 2;
if (ans > 0)
r = (l + r - 1) / 2;
else
l = (l + r + 2) / 2;
}
else if (last == l) {
ans = Guess(r);
last = r;
if (ans == 0) return (l + r) / 2;
if (ans > 0)
l = (l + r + 2) / 2;
else
r = (l + r - 1) / 2;
}
else {
// (kitas + last)/2 == mid
int kitas = 2 * mid - last;
printf("kitas = %d\n", kitas);
if (1 <= kitas and kitas <= N) {
ans = Guess(kitas);
int nxt = kitas;
if (ans == 0) return (last + kitas) / 2;
if ((ans > 0 and last < kitas) or (ans < 1 and kitas < last))
l = (last + kitas + 2) / 2;
else
r = (last + kitas - 1) / 2;
last = nxt;
} else {
if (last < l) Guess(l), last = l;
else Guess(r), last = r;
}
}
}
printf("returninu %d\n", l);
return l;
}
/* Look for:
* special cases (n=1?)
* overflow (ll vs int?)
* the exact constraints (multiple sets are too slow for n=10^6 :( )
* array bounds
*/
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
416 ms |
36732 KB |
잘못된 접근입니다. |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
427 ms |
36856 KB |
잘못된 접근입니다. |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
427 ms |
36728 KB |
잘못된 접근입니다. |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Execution timed out |
10007 ms |
262144 KB |
Time limit exceeded |
