이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#define fast ios_base::sync_with_stdio(0),cin.tie(0),cout.tie(0)
#include <bits/stdc++.h>
using namespace std;
#define sqr 200
#define mid (l+r)/2
#define pb push_back
#define ppb pop_back
#define fi first
#define se second
#define lb lower_bound
#define ub upper_bound
#define ins insert
#define era erase
#define C continue
#define mem(dp,i) memset(dp,i,sizeof(dp))
#define mset multiset
typedef long long ll;
typedef short int si;
typedef long double ld;
typedef pair<int,int> pi;
typedef pair<ll,ll> pll;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<pi> vpi;
typedef vector<pll> vpll;
const ll mod=1e9+7;
const ll inf= 4e18;
const ld pai=acos(-1);
#include "paint.h"
#include <cstdlib>
int n ,k ;
string s;
int a[200009];
int bs[200009];
int yes[200009][2];
int dp[200009][109];
void upd(int l,int r,int t){
yes[l][t]++;
yes[r+1][t]--;
}
int sum(int l,int r){
if ( l>r || r>=n )return -1;
int x=bs[r];
if(l)x-=bs[l-1];
return x;
}
int bt(int id,int crnt){
if(id==n)return (crnt==k);
int &ret=dp[id][crnt];
if(ret!=-1) return ret;
ret=0;
if(s[id]=='_'){
ret=bt(id+1,crnt);
}
if(s[id]=='.'){
ret=bt(id+1,crnt);
if(ret>0)upd(id,id,0);
int z=1;
if(crnt<k){
int l=id,r=id+a[crnt]-1;
int Sum=sum(l,r);
if(Sum!=a[crnt]) z=0;
if(r+1<n && s[r+1]=='X') z=0;
if(z){
z=bt(min(r+2,n),crnt+1);
if(z){
upd(l,r,1);
upd(r+1,r+1,0);
}
}
ret=max(ret,z);
}
}
if(s[id]=='X' && crnt<k){
int l=id,r=id+a[crnt]-1;
int Sum=sum(l,r);
if(Sum!=a[crnt])return ret=0;
if(r+1<n && s[r+1]=='X') return ret=0;
ret=bt( min(r+2,n) ,crnt+1);
if(ret){
upd(l,r,1);
upd(r+1,r+1,0);
}
}
else if(s[id]=='X')return ret=0;
return ret;
}
string solve_puzzle(string S , vector<int> c) {
mem(dp,-1);
s=S;
n=S.size();
k=c.size();
for(int i=0;i<n;i++){
bs[i]=(s[i]!='_');
if(i)bs[i]+=bs[i-1];
}
for(int i=0;i<k;i++)a[i]=c[i];
bt(0,0);
for(int i=1;i<n;i++){
for(int j=0;j<2;j++){
yes[i][j]+=yes[i-1][j];
}
}
string ans="";
for(int i=0;i<n;i++){
if(s[i]!='.'){
ans+=s[i];
C;
}
if(yes[i][0] && yes[i][1])ans+='?';
else if(yes[i][0])ans+='_';
else ans+='X';
}
return ans;
}
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