이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma GCC target("avx2")
//#pragma GCC optimize("O3")
//# include <x86intrin.h>
# include <bits/stdc++.h>
# include <ext/pb_ds/assoc_container.hpp>
# include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
template<typename T> using ordered_set = tree <T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define _USE_MATH_DEFINES_
#define ll long long
#define ld long double
#define Accepted 0
#define pb push_back
#define mp make_pair
#define sz(x) (int)(x.size())
#define every(x) x.begin(),x.end()
#define F first
#define S second
#define lb lower_bound
#define ub upper_bound
#define For(i,x,y) for (ll i = x; i <= y; i ++)
#define FOr(i,x,y) for (ll i = x; i >= y; i --)
#define SpeedForce ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0)
// ROAD to... Red
inline void Input_Output () {
//freopen(".in", "r", stdin);
//freopen(".out", "w", stdout);
}
const double eps = 0.000001;
const ld pi = acos(-1);
const int maxn = 1e7 + 9;
const int mod = 1e9 + 7;
const ll MOD = 1e18 + 9;
const ll INF = 1e18 + 123;
const int inf = 2e9 + 11;
const int mxn = 1e6 + 9;
const int N = 1e6 + 123;
const int M = 22;
const int pri = 997;
const int Magic = 2101;
const int dx[] = {-1, 0, 1, 0};
const int dy[] = {0, -1, 0, 1};
int n, m;
struct css {
ll s, t, p;
} a[N], b[N];
ll dp[2020][2020];
int main () {
SpeedForce;
cin >> n >> m;
for (int i = 1; i <= n; i ++) {
cin >> a[i].s >> a[i].t >> a[i].p;
a[i].s += a[i-1].s;
}
for (int i = 1; i <= m; i ++) {
cin >> b[i].s >> b[i].t >> b[i].p;
b[i].s += b[i-1].s;
}
for (int i = 0; i <= n; i ++) {
for (int j = 0; j <= m; j++)
dp[i][j] = -INF * (i + j > 0);
}
for (int i = 0; i <= n; i ++) {
// cout << "for : " << i << '\n';
for (int j = 0; j <= m; ++j) {
if (i < n) {
dp[i+1][j] = max(dp[i+1][j], dp[i][j] + (a[i+1].s + b[j].s <= a[i+1].t ? a[i+1].p : 0));
}
if (j < m) {
dp[i][j+1] = max(dp[i][j+1], dp[i][j] + (a[i].s + b[j+1].s <= b[j+1].t ? b[j+1].p : 0));
}
// cout << j << ' ' << dp[i][j] << '\n';
}
}
cout << dp[n][m] << '\n';
return Accepted;
}
// B...a
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